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cialit0506
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yezz
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Yeap, got it. Thanks a million :)
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Sunchaser20
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yezz

(x-y)(x+y) = (x+5)(y-5)

if we assume that (x-y) = (x+5) thus y = -5 and if we assumed that(x+y) = (y-5) = then x=-5 either ways /y/=/x/
x = +or-ve 5 and so is y ie // is the same .............suff
If a*b=c*d, it's not right to assume that a is equal either to c or d. a is a factor or a multiple of either c or d.
In this problem if x=5, than \(25-y^2=10*y-50\)
\(y^2+10*y-75=0\)
which gives us 2 solutions: y1=5 and y2=-15
And as we are not given that x and y are integers, we can plug in any value of x and solve for y.
Hence, insuff. Nevertheless, working out a solution when x=y is necessary to prove that statement 1 is insuff. If there were no solution when x=y at all, then Stat.1 would be sufficient and the answer would be "no".



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