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# Did the XYZ Corporation have higher sales in 1988 or in 1989? Assume

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Math Expert
Joined: 02 Sep 2009
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Did the XYZ Corporation have higher sales in 1988 or in 1989? Assume  [#permalink]

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17 Oct 2017, 07:16
1
1
00:00

Difficulty:

45% (medium)

Question Stats:

59% (01:21) correct 41% (01:36) wrong based on 44 sessions

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Did the XYZ Corporation have higher sales in 1988 or in 1989? Assume sales are positive.

(1) In 1988, the sales were twice the average (arithmetic mean) of the sales in 1988, 1989, and 1990.
(2) In 1990, the sales were 3 times those in 1989.

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Re: Did the XYZ Corporation have higher sales in 1988 or in 1989? Assume  [#permalink]

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17 Oct 2017, 08:08
Bunuel wrote:
Did the XYZ Corporation have higher sales in 1988 or in 1989? Assume sales are positive.

(1) In 1988, the sales were twice the average (arithmetic mean) of the sales in 1988, 1989, and 1990.
(2) In 1990, the sales were 3 times those in 1989.

Let Sales in 1988, 1989, 1990, be x, y, z respectively.

Is x greater or y?

Statment 1) y=2(x+y+z/3) ==> y=2x+2z

Sales is positive Hence y is greater

A is sufficient

Statment 2)Don't have any info about 1988 - Not Sufficient

A

Bunuel is it Correct?
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Re: Did the XYZ Corporation have higher sales in 1988 or in 1989? Assume  [#permalink]

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23 Oct 2017, 09:57
I went with A.
Based on statement 1, I let x=1988, y=1989 and z=1990. (x+y+z)/3=a and x=2a.
Substituted 2a for x (2a+y+z)=3a
Solved for a, a=y+z
Since, x=2a, x=2y+2z, given sales are positive, x, which is 1988’s sales must be larger than 1989 or 1990 for that matter. Sufficient.
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I'd love to hear any feedback or ways to improve my problem solving. I make a lot of silly mistakes. If you've had luck improving on stupid mistakes, I'd love to hear how you did it.

Also, I appreciate any kudos.

Re: Did the XYZ Corporation have higher sales in 1988 or in 1989? Assume &nbs [#permalink] 23 Oct 2017, 09:57
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