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03 Dec 2010, 01:20
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This is bothering the hell out of me. I know that if the last two digits of a number added together are divisible by 4 then the number is divisible by 4. In addition if a number is divisible by 3 and 4 then it is divisible by 12. I also know from simple math that 96 is divisible by all 3. However, when you add 9 + 6 you get 15. A number not divisible by 4. Is 96 just an exception to this rule, or are there more loop holes in other places as well? Thank you.
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03 Dec 2010, 01:42
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mmcooley33
The red part is not correct. The number is divisible by 4 if the last two digits form a number divisible by 4.
Sum of the digits rule work only for 3 and 9:
3 - If the sum of the digits is divisible by 3, the number is also.
9 - If the sum of the digits is divisible by 9, so is the number.
For more check on number theory and divisibility check: math-number-theory-88376.html
03 Dec 2010, 02:13
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cheers, apparantly im the a-hole. haha
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This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
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