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11 Jul 2011, 07:05
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
80% (01:17) correct
20%
(01:35)
wrong
based on 5
sessions
History
Date
Time
Result
Not Attempted Yet
hey,
In the book it says follow [spoiler].12y=9[/spoiler] but I want to ask you experts whether my way is ok too:
x/y = 96.12 --> .12(100) --> 12/100 --> 3/25
So the remainder is 3 or a multiple of 3 and the divisor is 25 or a multiple of 25.
Since the questions says the remainder is 9 which is 3 times the remainder I got from the above fraction (3/25) I would have to multiply 25 by 3 as well to get what y equals which is [spoiler]75. Hence the right answer. But is my method ok?[/spoiler]
In the book it says follow [spoiler].12y=9[/spoiler] but I want to ask you experts whether my way is ok too:
x/y = 96.12 --> .12(100) --> 12/100 --> 3/25
So the remainder is 3 or a multiple of 3 and the divisor is 25 or a multiple of 25.
Since the questions says the remainder is 9 which is 3 times the remainder I got from the above fraction (3/25) I would have to multiply 25 by 3 as well to get what y equals which is [spoiler]75. Hence the right answer. But is my method ok?[/spoiler]
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Problem Solving (PS) Forum
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12 Jul 2011, 01:09
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well....
you can say that z/y= 96 + (12/100)
12/100= 3/25
so y must be 25 or multiple of 25
and only 75 is multiple of 25 so you don't need to do the multiplication process
best wishes on your prep.
you can say that z/y= 96 + (12/100)
12/100= 3/25
so y must be 25 or multiple of 25
and only 75 is multiple of 25 so you don't need to do the multiplication process
best wishes on your prep.
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Problem Solving (PS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
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