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Division R of Company Q has 1,000 employees. What is the [#permalink]
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30 Nov 2005, 23:34
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Division R of Company Q has 1,000 employees. What is the average (arithmetic mean) annual salary of the employees at Company Q? (1)The average annual salary of the employees in Division R is $30,000. (2)The average annual salary of the employees at Company Q who are not in Division R is $35,000.
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getzgetzu wrote: Division R of Company Q has 1,000 employees. What is the average (arithmetic mean) annual salary of the employees at Company Q?
(1)The average annual salary of the employees in Division R is $30,000. (2)The average annual salary of the employees at Company Q who are not in Division R is $35,000.
1) No suff We do not have info of any other division
2) Not suff  No info on division R/ no idea of no of employees in other divisions
1 and 2 together not suff as we do not know no of people working in other divs
Hence E



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We do not know the total number of employees in the company.
Therefore, (E)



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Division R of Company Q has 1,000 employees. What is the average (arithmetic mean) annual salary of the employees at Company Q?
(1) The average annual salary of the employees in Division R is $30,000.
(2) The average annual salary of the employees at Company Q who are not in Division R is $35,000.
A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
D. EACH statement ALONE is sufficient.
E. Statements (1) and (2) TOGETHER are NOT sufficient.
From A we can work out that the overall salary cost for division A is $3m INSUFF
From b we cannot really tell much, since we don't know how many employees remain INSUFF
Combined both still does not help.
ANSWER E.



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Division R of Company Q has 1,000 employees. What is the average (arithmetic mean) annual salary of the employees at Company Q?
(1) The average annual salary of the employees in Division R is $30,000.
(2) The average annual salary of the employees at Company Q who are not in Division R is $35,000.
A IS NOT SUFF
B IS NOT SUFF
BOTH TOGETHER
INSUFF TOO
MY ANSWER IS E



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Re: division [#permalink]
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14 Oct 2008, 15:01
Jcpenny wrote: Division R of Company Q has 1,000 employees. What is the average (arithmetic mean) annual salary of the employees at Company Q? (1) The average annual salary of the employees in Division R is $30,000. (2) The average annual salary of the employees at Company Q who are not in Division R is $35,000. A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient. B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient. C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient. D. EACH statement ALONE is sufficient. E. Statements (1) and (2) TOGETHER are NOT sufficient. E 1. No Info about other divisions Not Sufficient 2.No Info about division R Not Sufficient Together R=1000 employees with an average of $30,000 non R = average of $35000, but # of employees ??? Not Sufficient



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Re: division [#permalink]
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14 Oct 2008, 15:03
[quote="Jcpenny"]Division R of Company Q has 1,000 employees. What is the average (arithmetic mean) annual salary of the employees at Company Q? (1) The average annual salary of the employees in Division R is $30,000. (2) The average annual salary of the employees at Company Q who are not in Division R is $35,000. Q = R+S = 1000+S what is TOTAL SALARY / 1000+(Q1000) TOTAL SALARY = TOTAL SALARY R + TOTAL SALARY S FROM ONE R TOTAL SALARY = 30,000*1000 ..........INSUFF FROM 2 TOTAL SALARY S = (s)*35,000........ E AND I HAVE TO GO TO SLEEP AS I HAVE AGRESSIVELY STARTED SILLY MISTAKES



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Re: division [#permalink]
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15 Oct 2008, 00:48
cant we just add both averages together and then divide over 2? i know it´s a stupid question but pls guys be so kind and tell me logically why not thank you



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Re: division [#permalink]
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15 Oct 2008, 01:29
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domleon wrote: cant we just add both averages together and then divide over 2? i know it´s a stupid question but pls guys be so kind and tell me logically why not thank you No. That cannot be done. Check the following. if total employees of division A is x1 and total salary is s1 then average = s1/x1. If rest of employees is x2 and total salary of these is s2 then average = s2/x2. Sum of the two averages = (s1/x1) + (s2/x2). However, average at the company level = (s1+s2)/(x1+x2) and this is not the same as (s1/x1) + (s2/x2). I hope, this helps.



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Re: division [#permalink]
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15 Oct 2008, 01:37
Its clearly (E) as no indication of distribution of number of employees among sector R and rest of the company. Guessing whats the level of this question ? Seems really easy one.



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Re: division [#permalink]
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15 Oct 2008, 06:15
if the number of employees of Q were given, then I would have gone for C. However, since that is missing, you'll not know the avg for Q.
E



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Re: DS  Averages / Arithematic Mean  OG 12 [#permalink]
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31 Mar 2009, 18:10
mrsmarthi wrote: Division R of Company Q has 1000 employees. What is the average annual salary of the employees at Company Q?
1) The average annual salary of the emplouees in Division R is $ 30,000. 2) The average annual salary of the employees at Company Q who are not in Division R is $ 35,000. stmnt 1  not suffic., only div. R is known stmnt 2  not sufic., nothing about div. R is known except the number of employees, which is not enough. let's combine  still not suffic. to answer the question. Therefore, it should be E.



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Re: DS  Averages / Arithematic Mean  OG 12 [#permalink]
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31 Mar 2009, 18:32
Average sal of employess in Q = Total salary of emp in Q/Total no of employees Total no of employees = 1000 + (no of employees not in R ). So both the statements are not sufficient as none of them give the number of employees not in division R. Hence E. pradeeep
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Re: DS  Averages / Arithematic Mean  OG 12 [#permalink]
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02 Apr 2009, 16:32
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Yes, E for me as well. C is the trap answer because it makes you think that since you have the two averages, you know the overall average.
Dont forget though that you need to know the total # of employees to determine overall average, which neither of the statements allow to us to deduce.



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Re: CAN NOT GET THIS DS QUESTION [#permalink]
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24 Mar 2010, 14:25
We can express the average annual salary of Company Q as: \(S = \frac{S_r * N_r+ S_{notr}*N_{notr}}{N_r+N_{notr}}\) where  \(S_r\)  The average annual salary of the employees in Division R  \(S_{notr}\)  The average annual salary of the employees who are not in Division R  \(N_r\)  The number of employees in Division R  \(N_{notr}\)  The number of employees who are not in Division R So, we don't know the number of employees who are not in Division R. You can also use huge/tiny numbers to check your answer. If \(N_{notr}=0\) or only 1 employee, S = 30K or will be very close to 30K. At the same time, if \(N_{notr}>>1000\), S will be very close to 35K. So we need to know at least \(\frac{N_{notr}}{N_r}\) ratio.
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Re: CAN NOT GET THIS DS QUESTION [#permalink]
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24 Mar 2010, 19:09
zest4mba wrote: Division R of Company Q has 1,000 employees. What is the average (arithmetic mean) annual salary of the employees at Company Q ? (1) The average annual salary of the employees in Division R is $30,000. (2) The average annual salary of the employees at Company Q who are not in Division R is $35,000.
I think if we take 1 and 2 together we could solve this for 30k+35k/2
but the anwer is E as we do not know the number of employees not in R Can someone explain this
thanks !! There are two values that we need to know in order to solve this problem. A. the number of employees at Company Q B. The amount of aggregate salary at Company Q From 1, we know that the aggregate salary in Division R is $30,000,000. Not sufficient. From 2, we know that the annual average salary of people who are not in Division R is $35,000. This does not tell us the aggregate salary outside of Division R nor the number of employees. With the information combined, we still do not have the two crucial pieces of information to solve the problem. Thus, E
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Re: DS  Averages / Arithematic Mean  OG [#permalink]
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02 Jun 2011, 14:41
1. Not sufficient
we dont know anything about the average of employees who are not in R and in Q.
2. Not sufficient
we dont know anything about the average of division R. and we dont know the number of employees of Q that are not in R.
together ,
we still dont know the number of employees of Q that are not in R.
Answer is E.



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Re: Division R of Company Q has 1000 employees. What is the [#permalink]
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26 Feb 2014, 09:54
Hi, Please add the OA. Thanks.
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Re: Division R of Company Q has 1000 employees. What is the [#permalink]
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26 Feb 2014, 10:23
mrsmarthi wrote: Division R of Company Q has 1000 employees. What is the average annual salary of the employees at Company Q?
1) The average annual salary of the emplouees in Division R is $ 30,000. 2) The average annual salary of the employees at Company Q who are not in Division R is $ 35,000. My take is E. Avg salary = Total salary/Total number of employees. none of the statements would give the total number of employees. Hence, it cannot be determined even by using both statements.
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Re: Division R of Company Q has 1000 employees. What is the [#permalink]
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27 Feb 2014, 04:36




Re: Division R of Company Q has 1000 employees. What is the
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