SajjadAhmad
Does 3^(r + s) = 27^6 ?
(1) r – s = 8
(2) 5r = 13s
Target question: Does 3^(r + s) = 27^6 ?This is a good candidate for
rephrasing the target question. To get the same base on both sides, rewrite 27 as 3^3.
We get:
3^(r + s) = (3^3)^6 Apply power of power rule to get:
3^(r + s) = 3^18 Now that the bases are the same, we can conclude that:
r + s = 18 So, we can REPHRASE the target question....
REPHRASED target question: Does r + s = 18? Statement 1: r – s = 8 Does this provide enough information to answer the
REPHRASED target question? No.
There are several values of r and s that satisfy statement 1. Here are two:
Case a: r = 8 and s = 0, in which case
r + s = 8 + 0 = 8Case b: r = 13 and s = 5, in which case
r + s = 13 + 5 = 18Since we cannot answer the
REPHRASED target question with certainty, statement 1 is NOT SUFFICIENT
Statement 2: 5r = 13s There are several values of r and s that satisfy statement 2. Here are two:
Case a: r = 0 and s = 0, in which case
r + s = 0 + 0 = 0Case b: r = 13 and s = 5, in which case
r + s = 13 + 5 = 18Since we cannot answer the
REPHRASED target question with certainty, statement 2 is NOT SUFFICIENT
Statements 1 and 2 combined Statement 1 tells us that r – s = 8
Statement 2 tells us that 5r = 13s
So, we have a system of two
different linear equations with 2 different variables.
Since we COULD solve this system for r and s, we could determine whether or not
r + s = 18, which means we COULD answer the
REPHRASED target question with certainty.
So,the combined statements are SUFFICIENT
Answer: C
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