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10 Oct 2019, 10:02
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Hi can anyone help me out with this:
we know
the angle formed by the diameter of the circle at the circumference is 90
but is corollary true?
if angle formed by chord is 90 at the circumference of a circle , is it true that chord will necessarily be diameter?
In case of square or rectangle inscribed in a circle , we take diagonal to pass through centre, by using property 2.plz clear
chetan2u
Bunuel
VeritasKarishma
we know
the angle formed by the diameter of the circle at the circumference is 90
but is corollary true?
if angle formed by chord is 90 at the circumference of a circle , is it true that chord will necessarily be diameter?
In case of square or rectangle inscribed in a circle , we take diagonal to pass through centre, by using property 2.plz clear
chetan2u
Bunuel
VeritasKarishma
Archived Topic
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This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
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10 Oct 2019, 10:07
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vanam52923
Yes, you are correct.
If any chord makes a 90 degree angle anywhere in circumference it is a diameter.
10 Oct 2019, 21:28
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vanam52923
Note that the length of the arc and angle subtended at the centre is a one-on-one relation.
Length of arc = Angle/360 * 2*pi*r
So each angle measurement will have a corresponding length of arc. Hence, given either the length of arc or the angle at the centre, we can the find the other uniquely.
Also, angle subtended at the centre is twice the angle subtended at the circumference. Hence, for any given length of arc, the measure of the angle subtended will stay the same and for any given measure of angle subtended, the length of the arc will be the same.
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Problem Solving (PS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
