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# Doug and Dave shared a pizza with 8 equally-sized slices. Doug wanted

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Doug and Dave shared a pizza with 8 equally-sized slices. Doug wanted  [#permalink]

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25 Mar 2019, 00:25
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35% (medium)

Question Stats:

71% (01:44) correct 29% (01:40) wrong based on 28 sessions

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Doug and Dave shared a pizza with 8 equally-sized slices. Doug wanted a plain pizza, but Dave wanted anchovies on half the pizza. The cost of a plain pizza was 8 dollars, and there was an additional cost of 2 dollars for putting anchovies on one half. Dave ate all the slices of anchovy pizza and one plain slice. Doug ate the remainder. Each paid for what he had eaten. How many more dollars did Dave pay than Doug?

(A) 1
(B) 2
(C) 3
(D) 4
(E) 5

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Re: Doug and Dave shared a pizza with 8 equally-sized slices. Doug wanted  [#permalink]

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25 Mar 2019, 00:55
Bunuel wrote:
Doug and Dave shared a pizza with 8 equally-sized slices. Doug wanted a plain pizza, but Dave wanted anchovies on half the pizza. The cost of a plain pizza was 8 dollars, and there was an additional cost of 2 dollars for putting anchovies on one half. Dave ate all the slices of anchovy pizza and one plain slice. Doug ate the remainder. Each paid for what he had eaten. How many more dollars did Dave pay than Doug?

(A) 1
(B) 2
(C) 3
(D) 4
(E) 5

In the pizza, if 8 slices cost 8 dollar, the cost of a slice is 1 dollar.

Since the cost of putting the anchovies on half the pizza(4 slices) is 2 dollars more
than the other half, each slice with anchovies will cost an additional 50 cents.

Dave ate all the slices of the anchovy pizza and a slice of plain pizza(4*1.5 + 1 = 7)

Therefore, Dave would have paid 7 - 3 = 4 dollars(Option D) more than Doug.
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Re: Doug and Dave shared a pizza with 8 equally-sized slices. Doug wanted  [#permalink]

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25 Mar 2019, 02:48
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Bunuel wrote:
Doug and Dave shared a pizza with 8 equally-sized slices. Doug wanted a plain pizza, but Dave wanted anchovies on half the pizza. The cost of a plain pizza was 8 dollars, and there was an additional cost of 2 dollars for putting anchovies on one half. Dave ate all the slices of anchovy pizza and one plain slice. Doug ate the remainder. Each paid for what he had eaten. How many more dollars did Dave pay than Doug?

(A) 1
(B) 2
(C) 3
(D) 4
(E) 5

cost of plain pizza per slice = 1$and cost of adding achovies = 2$ for half pizza
total effective cost of Pizza = 1*8 + 2 = 10 $slices eat by Dave = 2+ 5 ; 7$ worth
and Doug 3 slices; 3$worth so Dave paid 7-3 ; 4$ more
IMO D
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Re: Doug and Dave shared a pizza with 8 equally-sized slices. Doug wanted  [#permalink]

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25 Mar 2019, 05:24
Bunuel wrote:
Doug and Dave shared a pizza with 8 equally-sized slices. Doug wanted a plain pizza, but Dave wanted anchovies on half the pizza. The cost of a plain pizza was 8 dollars, and there was an additional cost of 2 dollars for putting anchovies on one half. Dave ate all the slices of anchovy pizza and one plain slice. Doug ate the remainder. Each paid for what he had eaten. How many more dollars did Dave pay than Doug?

(A) 1
(B) 2
(C) 3
(D) 4
(E) 5

I think the answer should be C.

There are 8 pizza slices.
The cost of the total pizza is $8 (for whole plain pizza)+$2 (for anchovies on half) = $10.00 Cost per slice =$$\frac{10.00}{8}$$ =$1.25

Dave had 5 slices - $1.25*5 =$6.25
Doug had the remaining 3 slices - $1.25*3 =$3.75

Difference is $6.25-$3.75 = $2.50. This answer when rounded is closest to C. _________________ If you liked my post, give me Kudos! Thanks! CEO Joined: 18 Aug 2017 Posts: 3016 Location: India Concentration: Sustainability, Marketing GPA: 4 WE: Marketing (Energy and Utilities) Re: Doug and Dave shared a pizza with 8 equally-sized slices. Doug wanted [#permalink] ### Show Tags 25 Mar 2019, 05:27 rodri102 seems you did not read the question properly; see highlighted part below.. rodri102 wrote: Bunuel wrote: Doug and Dave shared a pizza with 8 equally-sized slices. Doug wanted a plain pizza, but Dave wanted anchovies on half the pizza. The cost of a plain pizza was 8 dollars, and there was an additional cost of 2 dollars for putting anchovies on one half. Dave ate all the slices of anchovy pizza and one plain slice. Doug ate the remainder. Each paid for what he had eaten. How many more dollars did Dave pay than Doug? (A) 1 (B) 2 (C) 3 (D) 4 (E) 5 I think the answer should be C. There are 8 pizza slices. The cost of the total pizza is$8 (for whole plain pizza)+$2 (for anchovies on half) =$10.00

Cost per slice =$$\frac{10.00}{8}$$ = $1.25 Dave had 5 slices -$1.25*5 = $6.25 Doug had the remaining 3 slices -$1.25*3 = $3.75 Difference is$6.25-$3.75 =$2.50. This answer when rounded is closest to C.

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Re: Doug and Dave shared a pizza with 8 equally-sized slices. Doug wanted  [#permalink]

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27 Mar 2019, 18:49
Bunuel wrote:
Doug and Dave shared a pizza with 8 equally-sized slices. Doug wanted a plain pizza, but Dave wanted anchovies on half the pizza. The cost of a plain pizza was 8 dollars, and there was an additional cost of 2 dollars for putting anchovies on one half. Dave ate all the slices of anchovy pizza and one plain slice. Doug ate the remainder. Each paid for what he had eaten. How many more dollars did Dave pay than Doug?

(A) 1
(B) 2
(C) 3
(D) 4
(E) 5

The cost of the pizza is 8 + 2 = $10. The cost of the plain half is 8/2 =$4; thus, the cost of the anchovy half is $6. Therefore, each plain slice is 4/4 =$1. Since Dave ate all the anchovy slices and one plain slice, he ate 6 + 1 = $7 worth of the pizza. So Doug ate 10 - 7 =$3 worth of the pizza. The difference is \$4.

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Re: Doug and Dave shared a pizza with 8 equally-sized slices. Doug wanted   [#permalink] 27 Mar 2019, 18:49
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