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DS: >?

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Senior Manager
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DS: >? [#permalink]

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New post 30 Aug 2008, 01:32
00:00
A
B
C
D
E

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Re: DS: >? [#permalink]

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New post 30 Aug 2008, 02:31
from 1)
2x - 2y = 1, x-y = 1/2
x=1, y=1/2 both positive!
x=-1, y= - 1.5 both negative

from 2)
x/y > 1, both could be positive or negitive!
-2/-2
2/2

IMO answer is E

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Re: DS: >? [#permalink]

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New post 30 Aug 2008, 06:52
i got C. Here's what I did :

from stat 1, you know x-y=1/2
from stat 2, you know that either both x and y are positive or both negative

now, plug in x=1/2 + y into stat 2 to get (1/2y + y) / y > 1 --> 1/2y +1 > 1 --> 1/2y >0

That means that 2y>0, and in turn y>0 ... if this is the case, for stat 2 to be true, x must be greater than 0 as well

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Re: DS: >? [#permalink]

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New post 30 Aug 2008, 07:59
from 1)
2x - 2y = 1, x-y = 1/2
x=1, y=1/2 both positive!
x=-1, y= - 1.5 both negative

from 2)
x/y > 1, both could be positive or negitive!
-2/-2
2/2

Here we have according to 1)
x = 1 , y= 1/2
then x/y = 2 > 1
but if x= -1 , y= -1.5
then x/y = 2/3 < 1 not satisfied

hence x and y are both positive

ans is C
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Re: DS: >? [#permalink]

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New post 30 Aug 2008, 08:07
I will go with C aswell

1) 2x-2y=1
2) x/y>1

x/y >1 --> means x and y have same sign and |x|>|y|


when both are +ve x>y
2x-2y=1 (true)

when both are -ve |x|>|y|
2x-2y=1 (always false)

So X and Y must be positive
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Re: DS: >? [#permalink]

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New post 30 Aug 2008, 19:52
OA is C

U guys all always get 51 is GMATPrep? : )

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Re: DS: >?   [#permalink] 30 Aug 2008, 19:52
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