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DS from Kaplan what is the value of x? 1. x^2 / 3 = x/81 2.

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DS from Kaplan

what is the value of x?

1. x^2 / 3 = x/81

2. x>0

i get C ...kaplan says its A.

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pitts20042006

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A

1. x^2 / 3 = x/81
divide both sides by x (does not matter if x is -ve or +ve because it is an equation and not an inequality)

x/3 = 1/81
x = 3/81 = 1/27

A is sufficient

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What if X=0?
A yields two values.
B gives many values
A+B --> 1/27

Thus, Answer should be C.

pitts20042006

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TRUE.

was trying to explain kaplan's stand ... NOT MINE :-D

:-D

wonder_gmat

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13 Dec 2003, 08:25

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A.

(1)
x┬▓/3 = x/81
x┬▓/x = 3/81 ... just showing extra step to resolve the issues raised by some here.
x = 1/27

(2) x > 0, doesn't tell us anything we don't know.

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13 Dec 2003, 08:27

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wonder_gmat

A.

(1)
x┬▓/3 = x/81
x┬▓/x = 3/81 ... just showing extra step to resolve the issues raised by some here.
x = 1/27

(2) x > 0, doesn't tell us anything we don't know.

even x= 0 is a solution to the equation.

is it not?

pitts20042006

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again the same question to wonder_gmat .. how can you divide by x if x were to be 0 ?

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pitts20042006

again the same question to wonder_gmat .. how can you divide by x if x were to be 0 ?

why do you need to divide?

x^2 / 3 - x/81 = 0

x ( 27x-1) = 0

x = 0 or x = 1/27

A not sufficient

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wonder_gmat

A.

(1)
x┬▓/3 = x/81
x┬▓/x = 3/81 ... just showing extra step to resolve the issues raised by some here.
x = 1/27

(2) x > 0, doesn't tell us anything we don't know.

wonder, thats wrong

for your division to work, you need to assume that x not equal to 0.

pitts20042006

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I never said you need to divide ... but wonder_Gmat did divide and so the question to him

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