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From the figure, we get two equations -

(i) r + t + x = 180 (from line segment R-S-T)
(ii) 90 + (180 - t) + (180 - r) + x = 360 (from quadrilateral PQSU)

can be solved.

C.
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paddyboy
From the figure, we get two equations -

(i) r + t + x = 180 (r = angles at two vertices opposite to point R in the equilateral triangle;t = same for equilateral triangle having point T)
(ii) 90 + (180 - t) + (180 - r) + x = 360

can be solved.

C.



Sorry for being dumb but I am still not able to get this. I am not getting idea how we got these equation. :oops:
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Its not you, its my explanation (extremely crappy)... updated now... hope thats better...
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paddyboy
Its not you, its my explanation (extremely crappy)... updated now... hope thats better...


Absolutely clear thanks for the explanation :)
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Thanks Paddyboy for the explaination.



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