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Piter
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DS - gmatprep - numbers 13 Sep 2007, 09:33
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!

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DS - gmatprep - numbers 13 Sep 2007, 10:05
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ds

A. is enough. if y is +ve, x has to be -ve.
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A was my answer, but OA is different
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ashkrs
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DS - gmatprep - numbers 13 Sep 2007, 10:19
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I think its E .

Stmnt 1
y > 0 Let say y = 5
if x = -2 , equation doesn’t hold
if x = 2 , equation doesn’t hold
if x = - 3 , equation is fine .

So cant determine from Stmtn 1

Stmnt 2
2x = 20 -5y
y could be anything . y =1 or -1 makes x positive and y = 5 makes x negative
So not sufficient again

Combing both
Doesn’t make any difference again y could be anything on positive side.
So E
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DS - gmatprep - numbers 13 Sep 2007, 10:50
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[quote="ashkrs"]I think its E .

Stmnt 1
y > 0 Let say y = 5
if x = -2 , equation doesn’t hold if x = 2 , equation doesn’t hold
can u explain how?
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DS - gmatprep - numbers 13 Sep 2007, 12:19
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ds

A. is enough. if y is +ve, x has to be -ve.
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another boooooooooooooooom...... huh ..

i was smelling D but forgot to apply the condition that -2x>3x.
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dahcrap
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DS - gmatprep - numbers 13 Sep 2007, 14:04
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dahcrap
Guys this is clear D.
OA D
but I still don't get why (2) is suf.
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From stmt 2, 2x + 5y = 20 => x = 10 - 5y/2
From the stem we know -2x > 3y => x < -3y/2. Moreover this statement implies if y > 0 then x < 0

From the 2 statements, 10 -5y/2 < -3y/2 => y > 10. This implies y > 0 so x < 0
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DS - gmatprep - numbers 13 Sep 2007, 14:58
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-2x > 3x

is x < 0 ?

Statement 1

y > 0

-2x > 3y = -X > 1.5y

since Y is positive then 1.5y is positive and -x has to be positive making x negative.

Sufficient

Statement 2

2x+5y=20 and

-2x > 3y

2x < -3y

then:

2x = 20-5y

20-5y < -3y

20 < 2y

10 < y

y is greater then 0, same logic as in statement 1

Sufficient

the answer is (D) ---> dahcrap is correct !

:)
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DS - gmatprep - numbers 13 Sep 2007, 20:18
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This is def. D.

-2x>3y

B/f approaching the Statements quickly think of values that suffice this inequality.

x=-5 y=-2. 10>-6

x=-5 y=2 10>6

x=5 y=-6 -10>-18

S1:

y>0. If Y is greater than 0 then X has to be negative. Look at the values above. Try more if you don't see this from the values above.

S2:

2x+5y-20=0

2x=20-5y

-2x>3y

2x<-3y

20-5y<-3y

20<2y
10<y

You can try values too for S2. Thats how I originally got D in 2min.



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Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
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