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New post 18 Oct 2008, 22:05
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A
B
C
D
E

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Is |x|=y-z?
1)x+y=z
2)x<0

I found this one good !!
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Re: ds-mod [#permalink]

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New post 21 Oct 2008, 03:53
Taking 1: x = z-y

Now if x is +ve, |x| = z-y but if its -ve then |x| = y-z. Now, our desired result is the latter. So we must combine B with A for the answer. Hence C
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New post 21 Oct 2008, 06:46
another C

x=y-z when x>0 or;

-x=y-z => x= z-y when x<0

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New post 21 Oct 2008, 11:18
I went with A)


Is |x|=y-z?

Can also be written as:

|x|- y = - z

Point 1- If x > 0 Then x - y = -z
Point 2- If x < 0 Then -x - y = -z

1)x+y=z

Not sufficient, based on point 1 and 2. We need to know if x>0 or x<0

2)x<0

Does not say anything about y and Z. Not sufficient.

Answer is C.

Last edited by bigfernhead on 22 Oct 2008, 06:40, edited 1 time in total.

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Re: ds-mod [#permalink]

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New post 21 Oct 2008, 16:08
spriya wrote:
Is |x|=y-z?
1)x+y=z
2)x<0

I found this one good !!


I go with A too

1. x = -(y-z)
|x| = y-z
Sufficient
2. No Sufficient

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New post 21 Oct 2008, 20:31
Is |x|=y-z?

Can also be written as:

|x|+ y = - z



How can you write the above? when you move y to the opposite side, it becomes -y and does not remain y.

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New post 22 Oct 2008, 00:12
C.

From stmt1: x = z-y. Hence |x| could be z-y or y-z depending upon the value of x is +ve or -ve.

Stmt2 together with A gives that information.

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New post 22 Oct 2008, 06:40
You're right. Just edited my post. Thanks.

icandy wrote:
Is |x|=y-z?

Can also be written as:

|x|+ y = - z



How can you write the above? when you move y to the opposite side, it becomes -y and does not remain y.

Kudos [?]: 287 [0], given: 5

Re: ds-mod   [#permalink] 22 Oct 2008, 06:40
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