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03 Jun 2008, 01:12
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N
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03 Jun 2008, 01:19
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C for me!
1. x is prime and smaller than 15, x=2, 3,...not suff
2. x-2 =15k
2.1 x-2 = 0, x= 2
2.2. x-2 = 15, x=17,
2.3 x-2 = 45, x =47
not suff
combine 1 and 2, x=2 suff
1. x is prime and smaller than 15, x=2, 3,...not suff
2. x-2 =15k
2.1 x-2 = 0, x= 2
2.2. x-2 = 15, x=17,
2.3 x-2 = 45, x =47
not suff
combine 1 and 2, x=2 suff
03 Jun 2008, 01:43
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even i feel the answer shld be E....
explanation : the first option ONLY wouldnt be sufficient..bcos prime numbers less than 15 can be 2, 3, 5, 7, 11 or 13...so no particular value... so A is out...
if we consider the second option ALONE , then we can have several values which satisfy the condition that (x-2) is a multiple of 5..
Even when we consider both the options - we can have 2 values of x i.e. 2 and 7...
(2-2) is a multiple of 5 (bcos 0 is perfectly divisible by 5.)..same is the case with 7...
so again we dont have JUST ONE value...
so i feel the answer is E... pls do let me know what u feel abt the apporpriateness of the explanation..
explanation : the first option ONLY wouldnt be sufficient..bcos prime numbers less than 15 can be 2, 3, 5, 7, 11 or 13...so no particular value... so A is out...
if we consider the second option ALONE , then we can have several values which satisfy the condition that (x-2) is a multiple of 5..
Even when we consider both the options - we can have 2 values of x i.e. 2 and 7...
(2-2) is a multiple of 5 (bcos 0 is perfectly divisible by 5.)..same is the case with 7...
so again we dont have JUST ONE value...
so i feel the answer is E... pls do let me know what u feel abt the apporpriateness of the explanation..
