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03 Dec 2006, 14:00
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03 Dec 2006, 14:45
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I get C:
From 1 and question S: (30+40+50+x+25)/5 = 40
=> x = 55
=> numbers are: 25,30,40,50,55
From 2: (30+40+50+p+45)/5 = 40
=> numbers are: 10,25,30,40,50
Together, this seems to imply T has the higher standard deviation. Either way, we dont need to know exactly, just the fact that we have all the numbers to do the calc is enough
From 1 and question S: (30+40+50+x+25)/5 = 40
=> x = 55
=> numbers are: 25,30,40,50,55
From 2: (30+40+50+p+45)/5 = 40
=> numbers are: 10,25,30,40,50
Together, this seems to imply T has the higher standard deviation. Either way, we dont need to know exactly, just the fact that we have all the numbers to do the calc is enough
03 Dec 2006, 14:51
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C
From 1)
Set S - 25, 30, 40, 50, 55 (calculate the last one from average)
We know the SD of Set S but don’t have any idea about the SD of T
From 2)
Set T - 30, 35, 40, 45, 50.
Together
30, 40 and 50 are common members. Other elements of these sets will decide which set has greater SD.
new elements of Set S are further away from the mean (40).
SD of Set S > SD of Set T
From 1)
Set S - 25, 30, 40, 50, 55 (calculate the last one from average)
We know the SD of Set S but don’t have any idea about the SD of T
From 2)
Set T - 30, 35, 40, 45, 50.
Together
30, 40 and 50 are common members. Other elements of these sets will decide which set has greater SD.
new elements of Set S are further away from the mean (40).
SD of Set S > SD of Set T
