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# DS: Triangle

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Manager
Joined: 05 Aug 2008
Posts: 91

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Schools: McCombs Class of 2012

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28 Dec 2008, 23:19
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Kudos [?]: 47 [0], given: 0

SVP
Joined: 17 Jun 2008
Posts: 1534

Kudos [?]: 279 [0], given: 0

Re: DS: Triangle [#permalink]

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29 Dec 2008, 00:41
Answer will be A.

In the diagram, angle ABD will also be x and hence, AD = DB. Additionally, DB = DC. Since, AD is known, DC is known.

Kudos [?]: 279 [0], given: 0

Manager
Joined: 05 Aug 2008
Posts: 91

Kudos [?]: 47 [0], given: 0

Schools: McCombs Class of 2012
Re: DS: Triangle [#permalink]

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29 Dec 2008, 00:51
A is the correct answer. Could you explain how you deduct from the digram that AD=DB?

thank you.

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SVP
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Kudos [?]: 279 [0], given: 0

Re: DS: Triangle [#permalink]

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29 Dec 2008, 02:25
smarinov wrote:
A is the correct answer. Could you explain how you deduct from the digram that AD=DB?

thank you.

Angle BDC = angle BAD + angle DBA
or, 2x = x + angle DBA
Or, angle DBA = x = angle BAD.
Hence, AD = DB.

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Re: DS: Triangle   [#permalink] 29 Dec 2008, 02:25
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# DS: Triangle

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