During a certain year, 80 percent of the visitors to the Smithsonian

Question

﻿During a certain year, 80 percent of the visitors to the Smithsonian Institution were United States citizens, 50 percent of the remaining visitors were Canadian or Mexican citizens, and 50 percent of the visitors who were not citizens of the United States, Canada, or Mexico were citizens of European countries. The number of United States citizens who visited the Smithsonian that year was approximately how many times the number of citizens of European countries who visited the Smithsonian that year?

A. 1.6
B. 4.8
C. 8
D. 16
E. 32

gmatophobia · Accepted Answer

We can use a tree to plot the information.

Let's assume that the number of visitors = 100

...80 percent of the visitors to the Smithsonian Institution were United States citizens...

Number of US Citizens = 80% of 100 = 80

Remaining = 100 - 80 = 20

...50 percent of the remaining visitors were Canadian or Mexican citizens...

Number of Canadian or Mexicans = 50% of 20 = 10

Remaining = 20 - 10 = 10

...50 percent of the visitors who were not citizens of the United States, Canada, or Mexico were citizens of European countries..

Number of Europeans = 50% of 10 = 05

Required Ratio=  \frac{80}{05} = 16

Option D

JeffTargetTestPrep · Answer

Total = US + Canada & Mexico + Europe + Others

Total = 100
US = 80
Canada & Mexico = (1/2)(100 – 80) = 10
Europe = (1/2)(100 – 80 – 10) = 5

To answer the question, we need the determine the following ratio:

US/Europe = 80/5 = 16

Answer: D

MartyMurray · Answer

Let's let the total number of visitors equal V.

﻿80 percent of the visitors to the Smithsonian Institution were United States citizens

United States citizens = .80V

50 percent of the remaining visitors were Canadian or Mexican citizens

Remaining visitors = V - .80V = .20V

Canadian or Mexican citizens = .50 x .20V = .10V

50 percent of the visitors who were not citizens of the United States, Canada, or Mexico were citizens of European countries

Visitors who were not citizens of the United States, Canada, or Mexico = .20V - .10V = .10V

Citizens of European countries = .50 x.10V = .05V

The number of United States citizens who visited the Smithsonian that year was approximately how many times the number of citizens of European countries who visited the Smithsonian that year?

United States citizens/Citizens of European countries = .80V/.05V = 16

The correct answer is (D).

Paras96 · Answer

﻿During a certain year, 80 percent of the visitors to the Smithsonian Institution were United States citizens, 50 percent of the remaining visitors were Canadian or Mexican citizens, and 50 percent of the visitors who were not citizens of the United States, Canada, or Mexico were citizens of European countries. The number of United States citizens who visited the Smithsonian that year was approximately how many times the number of citizens of European countries who visited the Smithsonian that year?

Let the no. of visitors to the Smithsonian Institution = 100.
The no. of visitors to the Smithsonian Institution who were United States citizens = 80
The no. of visitors to the Smithsonian Institution who were Canadian or Mexican citizens = 50%x(100-80)=10
The no. of visitors to the Smithsonian Institution who were citizens of European countries = 50%x(100-80-10)=5

The number of United States citizens who visited the Smithsonian that year was approximately the number of citizens of European countries who visited the Smithsonian that year = 80/5 = 16

Hence D

Apk641 · Answer

Lets use simple numbers to better understand

Total Visitors= 100
US visitors= 80
Canada & Mexico= .5*20=10  20 represents the remainder  
Total not US, Canada & Mexico =10
European 10*.05=5

US/European = 80/5
=16

bumpbot · Answer

Automated notice from GMAT Club BumpBot: 

A member just gave Kudos to this thread, showing it’s still useful. I’ve bumped it to the top so more people can benefit. Feel free to add your own questions or solutions.

 This post was generated automatically.

During a certain year, 80 percent of the visitors to the Smithsonian

Prep Toolkit

Top 5 GMAT Debrief Videos

615 to 715 in 15 Days (Ria's Strategies)

More than Quant/Verbal Abilities: Speed vs. Accuracy

745 with Only Self-Prep and GMAT Club

From 555 to 765: 210-point Improvement

Perfect 805 Score Debrief by Julia

My Rewards

GMAT Problem Solving (PS) Questions

During a certain year, 80 percent of the visitors to the Smithsonian

Prep Toolkit

615 to 715 in 15 Days (Ria's Strategies)

More than Quant/Verbal Abilities: Speed vs. Accuracy

745 with Only Self-Prep and GMAT Club

From 555 to 765: 210-point Improvement

Perfect 805 Score Debrief by Julia

My Rewards