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01 May 2011, 12:48
1
8
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Difficulty:

55% (hard)

Question Stats:

69% (02:03) correct 31% (02:04) wrong based on 232 sessions

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During a sale, a clothing store sold each shirt at a price of $15 and each sweater at a price of$25.00 Did the store sell more sweaters than shirts during the sale?

1) The average of the prices of all of the shirts and sweaters that the store sold during the sale was $21.00 2) The total of the prices of all of the shirts and sweaters that the store sold during the sale was$420.00
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Joined: 02 Sep 2009
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01 May 2011, 14:52
WE can do this without even framing eqn.

Stat 1 says that avg of all shirts and sweaters = 21.00$means its closer to the price of sweaters ($25) vis-a-vis that of shirts ($20) hence more of sweaters must have been sold. hence statement 1 alone is sufficient to answer the question stat 2 says that 15 shirts + 25 sweaters = 420 hence cannot be solved. thus Ans - A Director Status: There is always something new !! Affiliations: PMI,QAI Global,eXampleCG Joined: 08 May 2009 Posts: 771 Re: During a sale, a clothing store sold each shirt at a price of$15 and  [#permalink]

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01 May 2011, 21:45
15 sh + 25 sw = 21(sh+sw)
4sw = 6sh
2sw = 3sh Sufficient.

15 sh + 25 sw = 420
3sh + 5sw = 84

5 * 16 = 80 (max sw = 16)
Hence by trial method sw = 15, sh = 3

3* 28 = 84 (max sh = 28)
hence by trial method 3*sh = 54 gives sw = 6
meaning sh = 18,sw = 6. Hence not sufficient.

Thus A.
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Joined: 16 May 2011
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28 Mar 2012, 06:53
from statement 2,

shirts x
sweaters y

15x +20y = 420

Can we say that since 60 is a common multiple between the 15 and 20, there will be more than one answer that can satisfy the equation?
If there is a common multiple for
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Joined: 06 Jul 2016
Posts: 351
Location: Singapore
Concentration: Strategy, Finance
During a sale, a clothing store sold each shirt at a price of $15 and [#permalink] ### Show Tags 20 Jul 2017, 11:07 1 agdimple333 wrote: During a sale, a clothing store sold each shirt at a price of$15 and each sweater at a price of $25.00 Did the store sell more sweaters than shirts during the sale? 1) The average of the prices of all of the shirts and sweaters that the store sold during the sale was$21.00
2) The total of the prices of all of the shirts and sweaters that the store sold during the sale was $420.00 Cost of Shirts =$15
Let shirts be x.
Cost of Sweaters = $25 Let sweaters be y. Is y>x? 1) $$\frac{15x + 25y}{x+y}$$ = 21 => 15x + 25y = 21x + 21y => $$\frac{x}{y}$$ = $$\frac{2}{3}$$ This basically means for every 2 shirts sold, 3 sweaters are sold. y > x. Sufficient. 2) 15x + 25y = 420 3x + 5y = 84 x = 8, y =12 => y > x x = 18, y = 4 => x > y Insufficient. A is the answer. _________________ Put in the work, and that dream score is yours! Target Test Prep Representative Status: Head GMAT Instructor Affiliations: Target Test Prep Joined: 04 Mar 2011 Posts: 2801 Re: During a sale, a clothing store sold each shirt at a price of$15 and  [#permalink]

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16 Jun 2018, 09:16
agdimple333 wrote:
During a sale, a clothing store sold each shirt at a price of $15 and each sweater at a price of$25.00 Did the store sell more sweaters than shirts during the sale?

1) The average of the prices of all of the shirts and sweaters that the store sold during the sale was $21.00 2) The total of the prices of all of the shirts and sweaters that the store sold during the sale was$420.00

The average of the prices of all of the shirts and sweaters that the store sold during the sale was $21.00. Since the average price of$21 is closer to $25 than it is to$15, there must be more sweaters sold than shirts. Statement one alone is sufficient.

Statement Two Alone:

The total of the prices of all of the shirts and sweaters that the store sold during the sale was $420.00. It’s possible that 12 sweaters and 8 shirts are sold since 12 x 25 + 8 x 15 = 300 + 120 =$420. It’s also possible that 6 sweaters and 18 shirts are sold since 6 x 25 + 18 x 15 = 150 + 270 = $420. In the former example, more sweaters were sold; however, in the latter example, more shirts were sold. Statement two alone is not sufficient. Answer: A _________________ # Jeffrey Miller Head of GMAT Instruction Jeff@TargetTestPrep.com 181 Reviews 5-star rated online GMAT quant self study course See why Target Test Prep is the top rated GMAT quant course on GMAT Club. Read Our Reviews If you find one of my posts helpful, please take a moment to click on the "Kudos" button. Intern Joined: 11 Mar 2018 Posts: 1 Re: During a sale, a clothing store sold each shirt at a price of$15 and  [#permalink]

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24 Jan 2020, 02:24
1
Bunuel wrote:
dchow23 wrote:
from statement 2,

shirts x
sweaters y

15x +20y = 420

Can we say that since 60 is a common multiple between the 15 and 20, there will be more than one answer that can satisfy the equation?
If there is a common multiple for

Not sure that I understand your question correctly but generally for such kind of question it's always better to check whether an equation whose solution must be integers only has one or more set of variables satisfying it.

As for the question.

During a sale, a clothing store sold each shirt at a price of $15 and each sweater at a price of$25. Did the store sell more sweaters than shirts during the sale?

(1) The average (arithmetic mean) of the prices of all the shirts and sweaters that the store sold during the sale was $21 --> since the average sale price of$21 is closer to $25 than to$15 then store sold more sweaters than shirts (sweaters have more weight in the weighted average and thus pulled it closer to $21). Sufficient. (2) The total of the prices of all the shirts and sweaters that the store sold during the sale was$420 --> 15x + 25y =420 --> 3x+5y=84. If x=8 and y=12 then x<y but if x=13 and y=5 then x>y. Not sufficient.

Hi Bunuel there is a typo, it should be x = 13 and y = 9.
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Joined: 02 Sep 2009
Posts: 61544
Re: During a sale, a clothing store sold each shirt at a price of $15 and [#permalink] ### Show Tags 26 Jan 2020, 23:46 lcueto wrote: Bunuel wrote: dchow23 wrote: from statement 2, shirts x sweaters y 15x +20y = 420 Can we say that since 60 is a common multiple between the 15 and 20, there will be more than one answer that can satisfy the equation? If there is a common multiple for Not sure that I understand your question correctly but generally for such kind of question it's always better to check whether an equation whose solution must be integers only has one or more set of variables satisfying it. As for the question. During a sale, a clothing store sold each shirt at a price of$15 and each sweater at a price of $25. Did the store sell more sweaters than shirts during the sale? (1) The average (arithmetic mean) of the prices of all the shirts and sweaters that the store sold during the sale was$21 --> since the average sale price of $21 is closer to$25 than to $15 then store sold more sweaters than shirts (sweaters have more weight in the weighted average and thus pulled it closer to$21). Sufficient.

(2) The total of the prices of all the shirts and sweaters that the store sold during the sale was $420 --> 15x + 25y =420 --> 3x+5y=84. If x=8 and y=12 then x<y but if x=13 and y=5 then x>y. Not sufficient. Answer: A. Hi Bunuel there is a typo, it should be x = 13 and y = 9. _____________________ Fixed the typo. Thank you. _________________ Re: During a sale, a clothing store sold each shirt at a price of$15 and   [#permalink] 26 Jan 2020, 23:46
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