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21 Jan 2025, 10:43
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vksunder
Where am I wrong in doing this problem? I assume x is a decimal (ie. 0.5)
So this time taken would simplify to:
\(\frac{100x}{(40)} + \frac{100(1-x)}{60}\)
Doing this, the math doesn't seem to work when fully expanded:
v = d/t so v = \(\frac{100}{equation_above }\) = \(\frac{120}{(x+2)}\)
21 Jan 2025, 11:19
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vedvar
They travelled x percent, whereas in your equation you are only considering x => if you want to assume that they travelled 50% then \(\frac{x}{100}\) will be 0.5
Total time taken = \(\frac{d}{40} * \frac{x}{100}\) + \(\frac{d}{60} * (1- \frac{x}{100})\)
= \(d * (\frac{x}{12000} + \frac{1}{60})\)
= \(d * (\frac{x+200 }{ 12000})\)
Total Average Speed = \(\frac{d }{ d * [(x+200) / 12000]}\) = \(\frac{12000 }{ x+200}\)
21 May 2025, 07:25
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I feel like the easiest way for me to get to the answer was with assuming the total distance as 100.
That makes x% as x, easier to visualise as distance imo, and the rest can be 100 - x.
Makes it pretty straightforward to solve from this point on, just plug it in to the formula for average speed.
That makes x% as x, easier to visualise as distance imo, and the rest can be 100 - x.
Makes it pretty straightforward to solve from this point on, just plug it in to the formula for average speed.
vksunder
