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d999
Each employee who works in company X works in exactly one of departments A, B, and C. What fraction of all the employees who work in company X work in department A?

(1) The ratio of the total number of employees who work in departments A and C to the number of employees who work in department B is 7 to 3.

(2) The average (arithmetic mean) of the numbers of employees who work in departments A, B, and C is times the number of employees who work in department A.
Solution:
Pre Analysis:
  • Each employee in company X works in exactly one of departments A, B and C
  • Let the number of employees working in these departments be a, b and c respectively
  • We are asked the value of \(\frac{a}{a+b+c}\)

Statement 1: The ratio of the total number of employees who work in departments A and C to the number of employees who work in department B is 7 to 3
  • Accordign to this statement, \(\frac{a+c}{b}=\frac{7}{3}\)
  • From this we can assume \(a+c=7x\) and \(b=3x\) and we can get \(a+b+c=7x+3x=10x\)
  • This will not help us get the value of \(\frac{a}{a+b+c}=\frac{a}{10x}\)
  • Thus, statement 1 alone is not sufficient and we can eliminate options A and D

Statement 2: The average (arithmetic mean) of the numbers of employees who work in departments A, B, and C is times the number of employees who work in department A
  • According to this statement, \(\frac{a+b+c}{3}=3a\) or \(\frac{a}{a+b+c}=\frac{1}{9}\)


Hence the right answer is Option B
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