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11 Oct 2020, 11:04
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Light bulb [Incandescent or Fluorescent]
\(\frac{40}{100}\) * I + \(\frac{90}{100}\) * F = \(\frac{80}{100}\) * (I + F)
=> F = 4I
Percent of the bulbs that are switched on are incandescent: \(\frac{(0.4 * I) }{ [0.8(I + F)]}\) * 100
=> \(\frac{(0.4 * I) }{ [0.8(I + 4I)] }\)* 100
=> \(\frac{(0.4 * I) }{ (4I)}\) * 100
=> 10
Answer D
\(\frac{40}{100}\) * I + \(\frac{90}{100}\) * F = \(\frac{80}{100}\) * (I + F)
=> F = 4I
Percent of the bulbs that are switched on are incandescent: \(\frac{(0.4 * I) }{ [0.8(I + F)]}\) * 100
=> \(\frac{(0.4 * I) }{ [0.8(I + 4I)] }\)* 100
=> \(\frac{(0.4 * I) }{ (4I)}\) * 100
=> 10
Answer D
14 Oct 2020, 04:17
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jabhatta2
Check the parallel example I gave above. When you have two solutions, one 40% alcohol and other 90% alcohol, are your weights the volumes of the two solutions or the volumes of the alcohol in the two solutions?
Alcohol is one of the ingredients and the weights are the solutions themselves, not an ingredient.
Similarly, here the weights are Incandescent lighted bulbs and Fluorescent lighted bulbs, not bulbs that are on. Incandescent Bulbs that are on and Incandescent bulbs that are off are two ingredients of all Incandescent bulbs.
11 Nov 2025, 09:51
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