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Each morning of her five-day workweek, Jane bought either a 50-cent mu

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Each morning of her five-day workweek, Jane bought either a 50-cent mu  [#permalink]

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New post 28 Mar 2019, 06:09
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A
B
C
D
E

Difficulty:

  25% (medium)

Question Stats:

79% (01:12) correct 21% (00:40) wrong based on 29 sessions

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Re: Each morning of her five-day workweek, Jane bought either a 50-cent mu  [#permalink]

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New post 28 Mar 2019, 06:34
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Bunuel wrote:
Each morning of her five-day workweek, Jane bought either a 50-cent muffin or a 75-cent bagel. Her total cost for the week was a whole number of dollars, How many bagels did she buy?

(A) 1
(B) 2
(C) 3
(D) 4
(E) 5


We need to fiddle with various scenarios involving $0.50 and $0.75 until we get 5 items that add to an INTEGER
We get: $0.50 + $0.50 + $0.50 + $0.75 + $0.75 = $3.00

So, Jane bought TWO bagels (at $0.75 each)

Answer: B

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Brent
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Re: Each morning of her five-day workweek, Jane bought either a 50-cent mu  [#permalink]

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New post 28 Mar 2019, 12:06
Bunuel wrote:
Each morning of her five-day workweek, Jane bought either a 50-cent muffin or a 75-cent bagel. Her total cost for the week was a whole number of dollars, How many bagels did she buy?

(A) 1
(B) 2
(C) 3
(D) 4
(E) 5


0.5x +0.75y = whole no
x=3 and y=2 only possible
x+y=5
IMO B
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Re: Each morning of her five-day workweek, Jane bought either a 50-cent mu  [#permalink]

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New post 31 Mar 2019, 11:51
Bunuel wrote:
Each morning of her five-day workweek, Jane bought either a 50-cent muffin or a 75-cent bagel. Her total cost for the week was a whole number of dollars, How many bagels did she buy?

(A) 1
(B) 2
(C) 3
(D) 4
(E) 5


Jane must have purchased 2 bagels for $1.50 and 3 muffins for $1.50, as that’s the only combination resulting in a whole number of dollars paid for the week..

Answer: B
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Re: Each morning of her five-day workweek, Jane bought either a 50-cent mu   [#permalink] 31 Mar 2019, 11:51
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