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Re: Each of a, b, c, and d is a positive integer less than 100. If when a [#permalink]
dushyant099 wrote:
Can you please provide answer for this post.
or can you explain a+c and not b+c means


please check the solution provided by me. Hoping it may help you :)
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Re: Each of a, b, c, and d is a positive integer less than 100. If when a [#permalink]
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Sajjad1994 wrote:
Each of a, b, c, and d is a positive integer less than 100. If when a is divided by d the remainder is 8 and when b is divided by c the remainder is 4, select one possible value for each a + c and b + d as well as one possible value for a + c but not b + d. Make only two selections, one in each column.

a + c and b + da + c but not b + d
0
1
2
4
5
9


a + c and b + d=9
a + c but not b + d=5


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The question says when a is divided by d the remainder is 8. This particular statement tells us not only something about d but also about a i.e.
a/d = rem 8
then d > 8
and a >= 8

Similarly, when b is divided by c the remainder is 4
b/c = rem 4
then c > 4
and b >= 4

from the above two statements we can conclude that the minimum value of a is 8 and c is 5 then a+c >= 13

I request Bunuel to please clarify my doubt.
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Re: Each of a, b, c, and d is a positive integer less than 100. If when a [#permalink]
pudu wrote:
If when a is divided by d the remainder is 8 means d>8. So d can be 9,10 etc.
and when b is divided by c the remainder is 4,means C>4. So c can be 5,6 etc.,
each a + c and b + d can be 9 because if a=4 then a+c can be 5+4=9 and b=0 then b+d can be 0+9=9

2. one possible value for a + c but not b + d. a+c should be at the minimum 5 and b+d should be at the minimum 9. Hence 5


Here a is positive integer less than 100; means the minimum value of a is 1 and hence the minimum value of a+c is 6 and b+d should be at the minimum 10. Hnece 6.
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Re: Each of a, b, c, and d is a positive integer less than 100. If when a [#permalink]
pudu wrote:
If when a is divided by d the remainder is 8 means d>8. So d can be 9,10 etc.
and when b is divided by c the remainder is 4,means C>4. So c can be 5,6 etc.,
each a + c and b + d can be 9 because if a=4 then a+c can be 5+4=9 and b=0 then b+d can be 0+9=9

2. one possible value for a + c but not b + d. a+c should be at the minimum 5 and b+d should be at the minimum 9. Hence 5

how did u get a is zero?
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Re: Each of a, b, c, and d is a positive integer less than 100. If when a [#permalink]
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Hi @Bunuel, @Chetan2u

Please help with this question.
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Re: Each of a, b, c, and d is a positive integer less than 100. If when a [#permalink]
pudu wrote:
If when a is divided by d the remainder is 8 means d>8. So d can be 9,10 etc.
and when b is divided by c the remainder is 4,means C>4. So c can be 5,6 etc.,
each a + c and b + d can be 9 because if a=4 then a+c can be 5+4=9 and b=0 then b+d can be 0+9=9

2. one possible value for a + c but not b + d. a+c should be at the minimum 5 and b+d should be at the minimum 9. Hence 5

­Hello pudu The assumptions made here do not satisfy the condition,
i.e 
when assumed a = 4 and d = 9, it does not meet the criteria "when a is divided by d we get a remainder of 8". Same is case for the other set of assumptions too.

BR,
Thanks
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Re: Each of a, b, c, and d is a positive integer less than 100. If when a [#permalink]
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