Deconstructing the QuestionWe are comparing the standard deviation of the
y-values generated by each linear equation as
x takes all integer values from
1 to
100.
For a linear transformation of the form \(y=ax+b\), the standard deviation changes by a factor of \(|a|\). The constant term \(b\) only shifts all values and does not affect spread.
So we only need to compare the absolute value of the coefficient of
x.
Step-by-stepIn choice A,\(y=\frac{x}{3}\)
the coefficient of
x is
\(\frac{1}{3}\)
In choice B,\(y=\frac{x}{2}+40\)
the coefficient of
x is
\(\frac{1}{2}\)
The \(+40\) does not affect the standard deviation.
In choice C,\(y=x\)
the coefficient is
\(1\)
In choice D,\(y=2x+50\)
the coefficient is
\(2\)
The \(+50\) does not affect the standard deviation.
In choice E,\(y=3x-20\)
the coefficient is
\(3\)
The \(-20\) does not affect the standard deviation.
Now compare the absolute values:
\(\frac{1}{3}, \frac{1}{2}, 1, 2, 3\)
The greatest is \(3\), so
choice E gives the greatest standard deviation.Answer: E