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15 Mar 2013, 23:17
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
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73% (02:04) correct
27%
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wrong
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Each writer of the local newspaper is paid as follows: a dollars for each of the first n stories each month, and a + b for each story thereafter, where a > b. How many more dollars will a writer who submits n + a stories in a month earn than a writer who submits n + b stories?
A. (a + b)(a + b + n)
B. a - b
C. a^2 - b^2
D. n(a - b)
E. an + bn - an
A. (a + b)(a + b + n)
B. a - b
C. a^2 - b^2
D. n(a - b)
E. an + bn - an
the answer is
Lets assume a=$10, b=$5, n=5 stories
For (n+a)=15 stories, the dollars earned is $10+10*$15=$160
For (n+b)=10 stories, the dollars earned is $10+5*$15=$85
Difference = $160 - $85 = $75
Now, input these variable values in the answer choices & observe only C equals $75.
my question is how it is right to add the number of stories with the money? as shown in the explanation
(n+a)=15 stories, and
(n+b)=10 stories
stories and money are two different things
Lets assume a=$10, b=$5, n=5 stories
For (n+a)=15 stories, the dollars earned is $10+10*$15=$160
For (n+b)=10 stories, the dollars earned is $10+5*$15=$85
Difference = $160 - $85 = $75
Now, input these variable values in the answer choices & observe only C equals $75.
my question is how it is right to add the number of stories with the money? as shown in the explanation
(n+a)=15 stories, and
(n+b)=10 stories
stories and money are two different things
16 Mar 2013, 00:14
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You can add the number of stories with the money, a,b and n represent numbers; the fact that they are "stories" or "money", it' s not relevant.
However the formula is:
\(a*n + (TS - n)(a + b)\)
TS= total stories
The difference is:
\([an + (n+a-n)(a+b)] - [an +(n+b-n)(a+b)]\)
\([an + a(a+b)] - [an + b(a+b)]\)
\(a(a+b) - b(a+b)\)
\(a^2+ab-b^2-ab\)
\(a^2-b^2\)
However the formula is:
\(a*n + (TS - n)(a + b)\)
TS= total stories
The difference is:
\([an + (n+a-n)(a+b)] - [an +(n+b-n)(a+b)]\)
\([an + a(a+b)] - [an + b(a+b)]\)
\(a(a+b) - b(a+b)\)
\(a^2+ab-b^2-ab\)
\(a^2-b^2\)
16 Mar 2013, 00:34
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Zarrolou
You can add the number of stories with the money, a,b and n represent numbers; the fact that they are "stories" or "money", it' s not relevant.
However the formula is:
\(a*n + (TS - n)(a + b)\)
TS= total stories
The difference is:
\([an + (n+a-n)(a+b)] - [an +(n+b-n)(a+b)]\)
\([an + a(a+b)] - [an + b(a+b)]\)
\(a(a+b) - b(a+b)\)
\(a^2+ab-b^2-ab\)
\(a^2-b^2\)
it's not question, but thank you anyway However the formula is:
\(a*n + (TS - n)(a + b)\)
TS= total stories
The difference is:
\([an + (n+a-n)(a+b)] - [an +(n+b-n)(a+b)]\)
\([an + a(a+b)] - [an + b(a+b)]\)
\(a(a+b) - b(a+b)\)
\(a^2+ab-b^2-ab\)
\(a^2-b^2\)
