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Each year, the members of a book club select novels and nonfiction boo

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Each year, the members of a book club select novels and nonfiction boo  [#permalink]

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New post 12 Jul 2018, 23:51
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A
B
C
D
E

Difficulty:

  45% (medium)

Question Stats:

75% (01:50) correct 25% (01:56) wrong based on 12 sessions

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Each year, the members of a book club select novels and nonfiction books to read. The club meets 3 times to discuss each novel and 5 times to discuss each nonfiction book they select. Last year, the club met 52 times and discussed 12 books. How many novels did the club discuss last year?


A) 2
B) 4
C) 5
D) 7
E) 14

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Each year, the members of a book club select novels and nonfiction boo  [#permalink]

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New post 13 Jul 2018, 00:33
Bunuel wrote:
Each year, the members of a book club select novels and nonfiction books to read. The club meets 3 times to discuss each novel and 5 times to discuss each nonfiction book they select. Last year, the club met 52 times and discussed 12 books. How many novels did the club discuss last year?


A) 2
B) 4
C) 5
D) 7
E) 14


Let x be the number of novels and y the number of non-fiction books.

From the question stem, we can deduce the following information
\(x + y = 12\) -> (1)
\(3x + 5y = 52\) -> (2)

Substituting y = 12 - x from (1) in (2), \(3x + 5(12 - x) = 52\)

Solving for x, we get \(3x + 60 - 5x = 52\) -> \(2x = 8\) -> \(x = 4\)
Therefore, the number of novels discussed last year is 4(Option B)
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Re: Each year, the members of a book club select novels and nonfiction boo  [#permalink]

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New post 13 Jul 2018, 00:36
1
+1 for B.

number of novels the club discussed = n
total = 12 books
the number of nonfiction books = 12 – n

Given,
Club met 3 times to discuss each novel and 5 times to discuss each nonfiction book, and the club met 52 times

Therefore,
3n + 5(12 – n) = 52.

Solving n=4

Hence, B.
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Re: Each year, the members of a book club select novels and nonfiction boo &nbs [#permalink] 13 Jul 2018, 00:36
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Each year, the members of a book club select novels and nonfiction boo

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