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# Easiest way to solve this problem

Author Message
Intern
Joined: 17 Oct 2008
Posts: 4
Easiest way to solve this problem [#permalink]

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17 Oct 2008, 17:31
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Hi Everyone,

I found this problem in GMAT Test (Pearson's). While I spent my time to manually solve it, I was wondering if there is any easier method to solve it. Any help in this regard is highly appreciated.

--------------

If M = 4$$^1/2$$ + 4$$^1/3$$ + 4$$^1/4$$, then value of M is

- Less than 3
- equal to 3
- between 3 and 4
- equal to 4
- greater than 4

Thanks
Ray
SVP
Joined: 29 Aug 2007
Posts: 2457
Re: Easiest way to solve this problem [#permalink]

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17 Oct 2008, 22:14
aray wrote:
Hi Everyone,

I found this problem in GMAT Test (Pearson's). While I spent my time to manually solve it, I was wondering if there is any easier method to solve it. Any help in this regard is highly appreciated.

--------------

If M = 4$$^1/2$$ + 4$$^1/3$$ + 4$$^1/4$$, then value of M is

- Less than 3
- equal to 3
- between 3 and 4
- equal to 4
- greater than 4

Thanks
Ray

4$$^1/2$$ = 2
4$$^1/3$$ > 1
4$$^1/4$$ > 1

so total > 4.
_________________

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GT

Intern
Joined: 17 Oct 2008
Posts: 4
Re: Easiest way to solve this problem [#permalink]

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19 Oct 2008, 11:49
Thanks. Thats the OA.
Re: Easiest way to solve this problem   [#permalink] 19 Oct 2008, 11:49
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# Easiest way to solve this problem

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