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Easy But Tricky

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jakolik
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Easy But Tricky [#permalink] New post   16 Aug 2010, 06:55
00:00
A
B
C
D
E

Difficulty:

35% (medium)

Question Stats:

84% (01:34) correct 16% (01:29) wrong based on 31 sessions
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A vendor sells 60 percent of apples he had and throws away 15 percent of the remainder. Next
day he sells 50 percent of the remainder and throws away the rest. What percent of his apples
does the vendor throw?

(A) 17
(B) 23
(C) 77
(D) None of these
(E) 75



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B
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vinay.kaipra
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Re: Easy But Tricky [#permalink] New post   16 Aug 2010, 07:11
Easy if you start with value 100. Only thing to note is that you have to add all the apples thrown away to get the percent. Good one. But should be easy for the guys who look carefully at the question I guess.
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Re: Easy But Tricky [#permalink] New post   16 Aug 2010, 08:15
Only trick is that you must not forget to add 6 apples that vendor has thrown earlier
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Re: Easy But Tricky [#permalink] New post   16 Aug 2010, 12:07
A, then I reread it and B. :)
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Re: Easy But Tricky [#permalink] New post   16 Aug 2010, 12:08
Also, "easy but tricky" could describe 90% of the problems on the GMAT! :)
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Re: Easy But Tricky [#permalink] New post   16 Aug 2010, 12:23
the answer should be B (23%)
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jakolik
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Re: Easy But Tricky [#permalink] New post   16 Aug 2010, 21:18
Exactly, it is a very easy problem but at the same time one can easily fall in the trap...
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Re: Easy But Tricky [#permalink] New post   16 Aug 2010, 23:09
jakolik wrote:
A vendor sells 60 percent of apples he had and throws away 15 percent of the remainder. Next
day he sells 50 percent of the remainder and throws away the rest. What percent of his apples
does the vendor throw?

(A) 17
(B) 23
(C) 77
(D) None of these
(E) 75


Take a number that is common to all figures given in the quesn (60, 15 and 50) and easy for calculations......I will take 300

Step 1 sells 60% = 300-180 = 120 throws away 15% = 120-18 = 102

Step 2 sells 50% = 102/2 = 51 so balance thrown away = 51

total apple thrown = (51+18) = 69
% of total apples = 69/300 = 23 answer (b)
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Re: Easy But Tricky [#permalink] New post   17 Aug 2010, 01:24
jakolik wrote:
A vendor sells 60 percent of apples he had and throws away 15 percent of the remainder. Next
day he sells 50 percent of the remainder and throws away the rest. What percent of his apples
does the vendor throw?

(A) 17
(B) 23
(C) 77
(D) None of these
(E) 75

Ans : B

I believe that the best way to tackle percentage problems is by considering a dummy value - 100.
In this case : Let's assume vendor has 100 apples in all.
1: 60 apples are sold. Remainder: 40 apples
2: 15% of 40 = 6 are thrown away; Remainder: 34 apples
3: 50% of 34 = 17 are sold and rest (17) are thrown away; Remainder = 0

From (2) & (3), Total no. of apples thrown away = 6 + 17 = 23

To sum it all up, based on our assumption of 100 apples, 23 are sold, i.e 23 %



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Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
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Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
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Re: Easy But Tricky [#permalink]
17 Aug 2010, 01:24
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