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# Eight Alaskan huskies are split into pairs to pull one of

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Senior Manager
Joined: 05 Mar 2006
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Eight Alaskan huskies are split into pairs to pull one of [#permalink]

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12 Aug 2006, 13:10
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Eight Alaskan huskies are split into pairs to pull one of four sleds in a race. How many different assignments of Huskies to sleds are possible?

32

64

420

1680

2520

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Intern
Joined: 23 Jul 2006
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12 Aug 2006, 15:29
HI...

I think is E.

For the first pair of dogs we have: 8C2
For the second pair : 6C2
For the third pair: 4C2
Finally, for the last pair: 2C2

THen, the total number is: 8C2 x 6C2 x 4C2 x 2C2 = 2520

is it OK?
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Woody crack the GMAT

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Manager
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Re: Hard Perm/Comb PS #1 [#permalink]

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13 Aug 2006, 14:46
agsfaltex wrote:
Eight Alaskan huskies are split into pairs to pull one of four sleds in a race. How many different assignments of Huskies to sleds are possible?

32

64

420

1680

2520

# of ways = 8c2 * 6c2 * 4c2* 1
=2520

Hence E

Heman

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SVP
Joined: 30 Mar 2006
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14 Aug 2006, 02:22
E.

For the first sled two huskies can be chosen in 8C2 = 28 ways
For the second sled two huskies can be chosen in 6C2 = 15 ways
For the third sled two huskies can be chosen in 4C2 = 6 ways
For the fourth sled two huskies can be chosen in 2C2 = 1 way

Total = 28*15*6 = 2520

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Manager
Joined: 26 Jun 2006
Posts: 151

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14 Aug 2006, 05:55
I got to 2520 part, but then I multiplied it by 4!=24, because I thought that Pair#1 can be assigned to one of the four sleds, Pair#2 can be assigned to one of remaining three, and so on...

I guess I overanalyzed it a little bit

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14 Aug 2006, 05:55
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# Eight Alaskan huskies are split into pairs to pull one of

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