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Updated on: 13 Aug 2018, 06:15
Originally posted by EgmatQuantExpert on 09 May 2018, 08:36.
Last edited by EgmatQuantExpert on 13 Aug 2018, 06:15, edited 7 times in total.
Last edited by EgmatQuantExpert on 13 Aug 2018, 06:15, edited 7 times in total.
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
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Application of Average Speed in Distance problems - Exercise Question #3
Every day in the morning Ross cycles for 2 hours. He always starts at a constant rate of 1 mile of distance in every 12 minutes. However, he takes different path for onward and return journey – the distance covered in the return journey is double of the distance covered in his onward journey. Also, his speed in the return journey becomes half of his original speed. What is his average speed in the whole journey?
To solve question 4: Question 4
To read the article: Application of Average Speed in Distance problems
Every day in the morning Ross cycles for 2 hours. He always starts at a constant rate of 1 mile of distance in every 12 minutes. However, he takes different path for onward and return journey – the distance covered in the return journey is double of the distance covered in his onward journey. Also, his speed in the return journey becomes half of his original speed. What is his average speed in the whole journey?
- A. 3 mph
B. 4 mph
C. 5 mph
D. 6 mph
E. 7 mph
To solve question 4: Question 4
To read the article: Application of Average Speed in Distance problems
Updated on: 14 May 2018, 00:33
Originally posted by EgmatQuantExpert on 09 May 2018, 08:37.
Last edited by EgmatQuantExpert on 14 May 2018, 00:33, edited 1 time in total.
Last edited by EgmatQuantExpert on 14 May 2018, 00:33, edited 1 time in total.
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Solution
Given:
• Every morning Ross cycles for 2 hours
• He always starts at a constant rate of 1 mile of distance in every 12 minutes
• He takes different routes for onward and return journey
- o The distance covered in the return journey is double of the distance covered in the onward journey
o The speed in the return journey becomes half of his original speed
To find:
• Average speed of Ross in his whole journey
Approach and Working:
• If Ross covers a constant rate of 1 mile of distance in every 12 minutes, then his speed in the onward journey = \(\frac{1}{12}\) * 60 mph = 5 mph
• As his speed becomes half in the return journey, his return journey speed = \(\frac{5}{2}\) mph = 2.5 mph
• Let us assume the distance covered in the onward journey is d miles
- o Therefore, the distance covered in the return journey is 2d miles
- o And similarly, the time taken to complete the return journey = \(\frac{2d}{2.5}\) hrs
We already know that the total journey time, combining both onward and return journey, is 2 hrs.
• Hence, we can say, \(\frac{d}{5} + \frac{2d}{2.5}\) = 2
- o Solving, we get d = 2 miles
- o Or, average speed = (d + 2d)/(d/5 + 2d/2.5)
Average speed = (2 + 4)/(2/5 + 4/2.5) mph = 3 mph
Hence, the correct answer is option A.
Answer: A
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Application of Average Speed in Distance problems - Exercise Question #3
Every day in the morning Ross cycles for 2 hours. He always starts at a constant rate of 1 mile of distance in every 12 minutes. However, he takes different path for onward and return journey – the distance covered in the return journey is double of the distance covered in his onward journey. Also, his speed in the return journey becomes half of his original speed. What is his average speed in the whole journey?
To solve question 4: Question 4
To read the article: Application of Average Speed in Distance problems
Every day in the morning Ross cycles for 2 hours. He always starts at a constant rate of 1 mile of distance in every 12 minutes. However, he takes different path for onward and return journey – the distance covered in the return journey is double of the distance covered in his onward journey. Also, his speed in the return journey becomes half of his original speed. What is his average speed in the whole journey?
- A. 3 mph
B. 4 mph
C. 5 mph
D. 6 mph
E. 7 mph
To solve question 4: Question 4
To read the article: Application of Average Speed in Distance problems
d - distance traveled in onward direction
given speed = 1 miles in 12 minutes = 5 miles in 60 minutes = 5 mph.
Time taken for onward journey = \(\frac{distance traveled}{time taken to travel}\) = \(\frac{d}{5}\)
Time taken for return journey = \(\frac{twice distance traveled for onward journey}{half the time taken for onward journey}\) = \(\frac{4d}{5}\)
Total time taken = \(\frac{d}{5}\) + \(\frac{4d}{5}\) = d.
Quote:
Every day in the morning Ross cycles for 2 hours
. it implies d =2.
Average speed = \(\frac{Distance traveled in onward journey + distance traveled in return journey}{Total time taken}\)
= \(\frac{d + 2d}{2}\)
= \(\frac{3d}{2}\)
= \(\frac{6}{2}\) = 3mph
Ans A
