Bunuel
Every time Cole tries to teach his old Collie dog, Cachaca, a new trick, it takes 3 minutes more than half the time it took to teach it the previous trick. If it took Cole m minutes to teach Cachaca the latest trick, and m>5, how long did it take him to teach Cachaca the trick before the previous trick?
A. 4m-18
B. 4m+9
C. 2m+9
D. 2m +12
E. m-6
OA is A
You can easily solve this question if you put any value of m > 6 and satisfy the eqn :
Now as per question - > 1/2t+3 = m
m = Time taken by Cole to teach Cachaca the latest trick
t = Time taken by Cole to teach Cachaca the previous trick
Now take any value greater than 5, let us take 6 min time taken by Cole to teach Cachaca the latest trick.
Putting this value 1/2t+ 3 = 6
t=6
so time taken by Cole to teach Cachaca the previous trick is 6 min.
Now put m = 6 in option you will get your ans :
A. 4m-18 ----> 24-18 = 6 ---> Answer
B. 4m+9 ------> 24+ 9 = 33 -> wrong
C. 2m+9 -----> 12+ 9 = 21
D. 2m +12 ---> 12+ 12 = 24 wrong
E. m-6 ------> 6-6 = 0