PKN
Bunuel
Every week, Renee is paid $40 per hour for the first 40 hours she works, and $80 per hour for each hour she works after the first 40 hours. How many hours would Renee have to work in one week to earn an average (arithmetic mean) of $60 per hour that week?
(A) 60
(B) 65
(C) 70
(D) 75
(E) 80
Renee makes $40*40 hours=$1600 in first 40 hours
Let 't' be the no of hours Renee would work.
Given, Renee makes $80 per hour for each hour she works after the first 40 hours. So, she makes an additional pay $80*(t-40)hours for every hour after 40 hours.
So, \(\frac{1600+80(t-40)}{t}=60\)
Or, 1600+80t-3200=60t
Or, 20t=1600
or, t=80 hours
Ans. (E)
PKNHi, Could you explain this part " So, she makes an additional pay $80*(t-40)hours for every hour after 40 hours.".
The way I was looking at it was:
Let x be the extra hours worked,
so to make the average equal to 60,
In the first 40 hours, amount earned = 1600.
Next x hours, amount earned = 80x (Since per hour = $80 after first 40 hrs)
(1600 +80x) / (40 + x) = 60
But on solving this I get 20x = 800 and x = 40 which is not in the options.
Could you please explain where am I going wrong?
Thanks a lot.