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# Exponent Subtraction

Author Message
Current Student
Joined: 03 Dec 2007
Posts: 83
Schools: NYU STERN

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04 Feb 2009, 17:08
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Hi All:

$$99,999^2-1^2=$$

a) (10^10) -2
b) $$(10^5 - 2)^2$$
c) $$10^4 (10^5 -2)$$
d) $$10^5 (10^4 -2)$$
e) $$10^5 (10^5 -2)$$
Senior Manager
Joined: 01 Feb 2005
Posts: 269

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04 Feb 2009, 17:20
1
KUDOS
e) 10^5 (10^5 -2) Best Answer....

Follows the principle (a^2 - b^2) = (a-b) (a+b)
SVP
Joined: 29 Aug 2007
Posts: 2467

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04 Feb 2009, 20:24
1
KUDOS
hardaway7 wrote:
Hi All:

$$99,999^2-1^2=$$

a) (10^10) -2
b) $$(10^5 - 2)^2$$
c) $$10^4 (10^5 -2)$$
d) $$10^5 (10^4 -2)$$
e) $$10^5 (10^5 -2)$$

= $$99,999^2-1^2$$
= $$(99,999+1)(99,999-1)$$
= $$(100,000)(99,998)$$
= $$(10^5)(100,000-2)$$
= $$(10^5)(10^5 - 2)$$
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Intern
Joined: 18 Jan 2009
Posts: 18
Schools: Kellogg, Ross, Darden, Kelley, UNC

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05 Feb 2009, 03:01
GMAT TIGER, excellent explanation!! +1 from me
Re: Exponent Subtraction   [#permalink] 05 Feb 2009, 03:01
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# Exponent Subtraction

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