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# Family seating

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Manager
Joined: 11 Apr 2009
Posts: 157

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21 May 2009, 09:44
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Question Stats:

0% (00:00) correct 100% (07:41) wrong based on 0 sessions

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A family consisting of one mother, one father, two daughters and a son is taking a road trip in a sedan. The sedan has two front seats and three back seats. If one of the parents must drive and the two daughters refuse to sit next to each other, how many possible seating arrangements are there?
28
32
48
60
120

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Intern
Joined: 21 May 2009
Posts: 1

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21 May 2009, 13:09

Good ques though!!
SVP
Joined: 07 Nov 2007
Posts: 1759
Location: New York

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21 May 2009, 13:11
gmatprep09 wrote:
A family consisting of one mother, one father, two daughters and a son is taking a road trip in a sedan. The sedan has two front seats and three back seats. If one of the parents must drive and the two daughters refuse to sit next to each other, how many possible seating arrangements are there?
28
32
48
60
120

PX
DDX

= Total No of ways - two daughters sit together
= 2*4! - 2 (choose 1 Parent for Driver seat)* 2(Daughters can be arranged themselves) * 2 (DD and X (backseat) arranged in themselves) * 2( X and X can be aranged in two ways)
=48 -2*2*2*2
=32

--== Message from GMAT Club Team ==--

This is not a quality discussion. It has been retired.

If you would like to discuss this question please re-post it in the respective forum. Thank you!

To review the GMAT Club's Forums Posting Guidelines, please follow these links: Quantitative | Verbal Please note - we may remove posts that do not follow our posting guidelines. Thank you.

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Re: Family seating   [#permalink] 21 May 2009, 13:11
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