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# Find the number of factors of a three digit even number xyz

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Joined: 19 Feb 2012
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Find the number of factors of a three digit even number xyz  [#permalink]

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Updated on: 27 May 2013, 04:47
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Question Stats:

62% (02:08) correct 38% (02:07) wrong based on 264 sessions

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Find the number of factors of a three digit even number xyz where x, y and z are distinct prime numbers (2, 3 and 5)

A. 8
B. 10
C. 12
D. 16
E. 24

Originally posted by kiran882 on 04 Mar 2012, 04:29.
Last edited by Bunuel on 27 May 2013, 04:47, edited 2 times in total.
Edited the question
Math Expert
Joined: 02 Sep 2009
Posts: 55801
Re: Find the number of factors of a three digit even number xyz  [#permalink]

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04 Mar 2012, 04:57
1
2
kiran882 wrote:
Find the number of factors of a three digit even number xyz where x, y and z are distinct prime numbers (2, 3 and 5)

A. 8
B. 10
C. 12
D. 16
E. 24

Since xyz is an even number then it's $$532=2^2*7*19$$ or $$352=2^5*11$$.

In either case the # of factors is 12:
For $$532=2^2*7*19$$ the # of factors will be $$(2+1)(1+1)(1+1)=12$$;
For $$352=2^5*11$$ the # of factors will be $$(5+1)(1+1)=12$$.

In case one doesn't know.
Finding the Number of Factors of an Integer

First make prime factorization of an integer $$n=a^p*b^q*c^r$$, where $$a$$, $$b$$, and $$c$$ are prime factors of $$n$$ and $$p$$, $$q$$, and $$r$$ are their powers.

The number of factors of $$n$$ will be expressed by the formula $$(p+1)(q+1)(r+1)$$. NOTE: this will include 1 and n itself.

Example: Finding the number of all factors of 450: $$450=2^1*3^2*5^2$$

Total number of factors of 450 including 1 and 450 itself is $$(1+1)*(2+1)*(2+1)=2*3*3=18$$ factors.

For more on number properties check: math-number-theory-88376.html

Hope it helps.
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Re: Find the number of factors of a three digit even number xyz  [#permalink]

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27 Jan 2017, 09:21
Bunuel wrote:

Since xyz is an even number then it's $$532=2^2*7*19$$ or $$352=2^5*11$$.

In either case the # of factors is 12:
For $$532=2^2*7*19$$ the # of factors will be $$(2+1)(1+1)(1+1)=12$$;
For $$352=2^5*11$$ the # of factors will be $$(5+1)(1+1)=12$$.

Why answer cannot be E-24. We have 2 even numbers 532 and 352. Both are giving 12 as # of factors. Question asks, Find the number of factors of a three digit even number xyz ? So, Can't we consider both the even numbers ?
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Joined: 02 Sep 2009
Posts: 55801
Re: Find the number of factors of a three digit even number xyz  [#permalink]

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27 Jan 2017, 09:29
1
vinnik wrote:
Bunuel wrote:

Since xyz is an even number then it's $$532=2^2*7*19$$ or $$352=2^5*11$$.

In either case the # of factors is 12:
For $$532=2^2*7*19$$ the # of factors will be $$(2+1)(1+1)(1+1)=12$$;
For $$352=2^5*11$$ the # of factors will be $$(5+1)(1+1)=12$$.

Why answer cannot be E-24. We have 2 even numbers 532 and 352. Both are giving 12 as # of factors. Question asks, Find the number of factors of a three digit even number xyz ? So, Can't we consider both the even numbers ?

No. Find the number of factors of a three digit even number xyz. xyz is one number.
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Re: Find the number of factors of a three digit even number xyz  [#permalink]

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28 Jan 2017, 00:32
Bunuel wrote:
No. Find the number of factors of a three digit even number xyz. xyz is one number.

Okay. Got it. Thanks
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Joined: 12 Aug 2015
Posts: 2609
Schools: Boston U '20 (M)
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Find the number of factors of a three digit even number xyz  [#permalink]

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28 Jan 2017, 04:16
Bunuel wrote:
kiran882 wrote:
Find the number of factors of a three digit even number xyz where x, y and z are distinct prime numbers (2, 3 and 5)

A. 8
B. 10
C. 12
D. 16
E. 24

Since xyz is an even number then it's $$532=2^2*7*19$$ or $$352=2^5*11$$.

In either case the # of factors is 12:
For $$532=2^2*7*19$$ the # of factors will be $$(2+1)(1+1)(1+1)=12$$;
For $$352=2^5*11$$ the # of factors will be $$(5+1)(1+1)=12$$.

In case one doesn't know.
Finding the Number of Factors of an Integer

First make prime factorization of an integer $$n=a^p*b^q*c^r$$, where $$a$$, $$b$$, and $$c$$ are prime factors of $$n$$ and $$p$$, $$q$$, and $$r$$ are their powers.

The number of factors of $$n$$ will be expressed by the formula $$(p+1)(q+1)(r+1)$$. NOTE: this will include 1 and n itself.

Example: Finding the number of all factors of 450: $$450=2^1*3^2*5^2$$

Total number of factors of 450 including 1 and 450 itself is $$(1+1)*(2+1)*(2+1)=2*3*3=18$$ factors.

For more on number properties check: math-number-theory-88376.html

Hope it helps.

Hi Bunuel.
I have a doubt in the highlighted part.

The question says -> x, y and z are distinct prime numbers (2, 3 and 5)
So shouldn't x,y,z be 2,3,5 respectively?
Why would they write x,y,z and then mention 2,3,5 against them.
Wouldn't GMAT specify the same?

Though the answer would not be affected but i guess a clarification would be helpful in similar questions.

Regards
Stone Cold.

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Posts: 1003
Location: India
Re: Find the number of factors of a three digit even number xyz  [#permalink]

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01 Feb 2019, 07:03
kiran882 wrote:
Find the number of factors of a three digit even number xyz where x, y and z are distinct prime numbers (2, 3 and 5)

A. 8
B. 10
C. 12
D. 16
E. 24

So the following numbers can be possible
235, 532, 352

Take factors of 1 of them
532 = 2*2*7*19

2^3 * 7^2 * 19^2

12

C
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Re: Find the number of factors of a three digit even number xyz   [#permalink] 01 Feb 2019, 07:03
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