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Five consecutive integers have a sum N. If all the integers are increased by the same amount so that the middle integer is doubled, what is the sum of the resulting numbers?
A. 2N
B. 2N + 1
C. 2N + 2
D. 2N + 3
E. 2N + 4
A. 2N
B. 2N + 1
C. 2N + 2
D. 2N + 3
E. 2N + 4
30 Dec 2016, 06:49
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(a-2)+(a-1)+a+(a+1)+(a+2)=N
5a=N
To double the middle term, we need to add 'a' to all the 5 terms, which means adding 5a(=N).
Resulting sum is 2N.
A.
Sent from my SM-G920I using GMAT Club Forum mobile app
5a=N
To double the middle term, we need to add 'a' to all the 5 terms, which means adding 5a(=N).
Resulting sum is 2N.
A.
Sent from my SM-G920I using GMAT Club Forum mobile app
30 Dec 2016, 07:36
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