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Five identical squares are arranged as shown above to form one large

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Bunuel
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Five identical squares are arranged as shown above to form one large [#permalink] New post   03 Feb 2022, 02:30
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Five identical squares are arranged as shown above to form one large shape. If the total area of the shape is 405, what is the perimeter of the shape?

A. 96
B. 108
C. 144
D. 162
E. 180

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zhanbo
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Re: Five identical squares are arranged as shown above to form one large [#permalink] New post   03 Feb 2022, 03:09
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405 / 5 = 81 = 9 * 9
Each side of the square is 9.

the perimeter of the shape = (3 * 4) * 9 = 108

Answer is (B).
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TarunKumar1234
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Re: Five identical squares are arranged as shown above to form one large [#permalink] New post   03 Feb 2022, 07:35
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Area of a single square = 405/5 = 81

Side of a square = Sqrt (81) =9; So, the perimeter = 9*(3*4) = 108

I think B. :)
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Re: Five identical squares are arranged as shown above to form one large [#permalink] New post   03 Feb 2022, 09:25
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Bunuel wrote:

Five identical squares are arranged as shown above to form one large shape. If the total area of the shape is 405, what is the perimeter of the shape?

A. 96
B. 108
C. 144
D. 162
E. 180

Show Spoiler
Attachment:
2.png



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There are five squares. Area =405
Area of each square = 405/5 = 81
Side of each square \(\sqrt{81}=9\)

Perimeter = 9x3x4= 108

Ans. B
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Re: Five identical squares are arranged as shown above to form one large [#permalink]
03 Feb 2022, 09:25
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