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Five women bought dresses in a store for an average price of $96 each. A sixth woman bought a dress for $30 more than the average of all six. How much did she pay
A) 276 B) 132 C) 126 D) 102 E) 101
I would appreciate answer with explaination. Thanks
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Five women bought dresses in a store for an average price of $96 each. A sixth woman bought a dress for $30 more than the average of all six. How much did she pay
A) 276 B) 132 C) 126 D) 102 E) 101
I would appreciate answer with explaination. Thanks
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x - price of dress #6 -> average = (x+5*96)/6 = x - 30 -> x*(5/6)=5*96/6+30 -> x = 96+30*6/5=96+36=132 -> B
Five women bought dresses in a store for an average price of $96 each. A sixth woman bought a dress for $30 more than the average of all six. How much did she pay
A) 276 B) 132 C) 126 D) 102 E) 101
I would appreciate answer with explaination. Thanks
Show more
Original sum : 5*96=480. Now the 6th's womens dress is x.
new avg: (480+x)/6=z we know x=z+30. now its (480+z+30)/6=6z. Just solve.
Five women bought dresses in a store for an average price of $96 each. A sixth woman bought a dress for $30 more than the average of all six. How much did she pay
A) 276 B) 132 C) 126 D) 102 E) 101
I would appreciate answer with explaination. Thanks
x - price of dress #6 -> average = (x+5*96)/6 = x - 30 -> x*(5/6)=5*96/6+30 -> x = 96+30*6/5=96+36=132 -> B
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Got B with the same approach
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.