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# For a finite sequence of nonzero numbers, the number of

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Manager
Joined: 05 Aug 2008
Posts: 88
Schools: McCombs Class of 2012
For a finite sequence of nonzero numbers, the number of [#permalink]

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03 Jan 2009, 22:12
For a finite sequence of nonzero numbers, the number of variations in sign is defined as the number of pairs of consecutive terms of the sequence for which the product of the two consecutive terms is negative. What is the number of variations in sign for the sequence 1, -3, 2, 5, -4, -6 ?

(A) One
(B) Two
(C) Three
(D) Four
(E) Five

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Manager
Joined: 05 Aug 2008
Posts: 88
Schools: McCombs Class of 2012

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04 Jan 2009, 14:36
it is, can you explain how you arrived at that solution?

thanks
Manager
Joined: 30 Dec 2008
Posts: 120

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04 Jan 2009, 16:49
1
you add the count.. if the product of the 2 consecutive numbers = negative.
here are the possibilities:
1st term x 2nd term = negative... that's 1
2nd term x 3rd term = negative... that's 2
3rd x 4th = positive
4th x 5th = negative..that's 3
5th x 6th = positive

Senior Manager
Joined: 23 May 2008
Posts: 387

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05 Jan 2009, 03:11
multiply the consecutive numbers and count when the sign of the multiplied number is negative.
Manager
Joined: 05 Aug 2008
Posts: 88
Schools: McCombs Class of 2012

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05 Jan 2009, 11:48
thanks for your detailed explanation cul3s.

When I first encountered this question I re-organized the numbers in order of magnitude, when I should of just used them the way they were given. I got misled since it says "consecutive"

thanks again.

--== Message from GMAT Club Team ==--

This is not a quality discussion. It has been retired.

If you would like to discuss this question please re-post it in the respective forum. Thank you!

To review the GMAT Club's Forums Posting Guidelines, please follow these links: Quantitative | Verbal Please note - we may remove posts that do not follow our posting guidelines. Thank you.
Re: Consecutive Numbers   [#permalink] 05 Jan 2009, 11:48
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# For a finite sequence of nonzero numbers, the number of

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