For a positive integer 4,6,7,9,11,12,14 and x is the median

Question

For a positive integer 4,6,7,9,11,12,14 and x is the median (9+x)/2 
(1) 6<x<=11
(2) x is even

the thing is that i dont agree with the OA on this one 
would appreciate if we guys can have some discussion on this

Thanks

alpha_plus_gamma · Answer

Should be A.

Since there are 8 numbers, If 6<x<=11 the median will be (9+x)/2

buffdaddy · Answer

i don't even understand the Q, :oops:

gmatcrook · Answer

I) Will go with E.

since (9+x)/2 is the median.

The series would look like:

4,6,7,9,x,11,12,14 - (in which case x could be 9,10 or 11)

or

4,6,7,x,9,11,12,14 - (in which case x could be 7,8 or 9)

Now consider - (A) 6<x<=11 --> x can be 7,8,9,10,11 so DOES NOT SUFFICE
(B) x is even --> x can be 8 or 10 so DOES NOT SUFFICE

Taken together still gives x as 8 or 10. Hence, A and B taken together also does not suffice. So, E.

II) If we strictly go by the placement of 'x' in the median (9+x)/2 which implies x >= 9
Then, B will suffice and x would be 10.
Hence, answer would be (B)

I'm not sure which one should be considered here. If it was actual GMAT I would pick B.

GMATBLACKBELT · Answer

Weird question.

The answer is A.

Essentially the question is asking is X equal to 7,8,9,10, or 11? b/c these numbers would be next to 9. Thus would be in the calculation for the median.

gmatcrook · Answer

Did I read the question wrong here?

pmenon · Answer

i agree, the wording of the question is not good. i took it to ask : for this given set of integers, is the median (9+x)/2 ?

A is sufficient for answering this question

For a positive integer 4,6,7,9,11,12,14 and x is the median

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