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For a positive integer n, the number n! is defined to be

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For a positive integer n, the number n! is defined to be  [#permalink]

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21 Dec 2018, 08:37
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Difficulty:

5% (low)

Question Stats:

83% (00:36) correct 17% (00:38) wrong based on 85 sessions

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For a positive integer n, the number n! is defined to be n(n - 1)(n - 2) ... (1). For example, 4! = 4(3)(2)(1). What is the value of 5! - 3!?

(A) 120
(B) 114
(C) 20
(D) 15
(E) 2

Project PS Butler : Question #92

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Re: For a positive integer n, the number n! is defined to be  [#permalink]

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21 Dec 2018, 09:32
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HKD1710 wrote:
For a positive integer n, the number n! is defined to be n(n - 1)(n - 2) ... (1). For example, 4! = 4(3)(2)(1). What is the value of 5! - 3!?

(A) 120
(B) 114
(C) 20
(D) 15
(E) 2

Project PS Butler : Question #92

$$5! - 3!$$

= $$5*4*3! - 3!$$

= $$3!( 5*4 - 1)$$

= $$3*2 ( 20 - 1 )$$

= $$6*19$$

= $$114$$, Answer must be (B)
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Re: For a positive integer n, the number n! is defined to be  [#permalink]

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21 Dec 2018, 10:33
HKD1710 wrote:
For a positive integer n, the number n! is defined to be n(n - 1)(n - 2) ... (1). For example, 4! = 4(3)(2)(1). What is the value of 5! - 3!?

(A) 120
(B) 114
(C) 20
(D) 15
(E) 2

Project PS Butler : Question #92

5!-3! = 5*4*3*2*1-3*2=3*2(5*4-1) = 6*19=114. This probably is a sub 600 level question though, not 600-700.
Re: For a positive integer n, the number n! is defined to be   [#permalink] 21 Dec 2018, 10:33
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