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04 Jun 2021, 07:45
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For all integers \(n \neq 1\), let \(<n> = \frac{n+1}{n-1}\). Which of the following has the greatest value ?
A. <0>
B. <2>
C. <3>
D. <4>
E. <5>
A. <0>
B. <2>
C. <3>
D. <4>
E. <5>
04 Jun 2021, 20:52
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Bunuel
For all integers \(n \neq 1\), let \(<n> = \frac{n+1}{n-1}\). Which of the following has the greatest value ?
A. <0>
B. <2>
C. <3>
D. <4>
E. <5>
A. <0>
B. <2>
C. <3>
D. <4>
E. <5>
A. \(<0> = \frac{0+1}{0-1}\) = -1
B. \(<2> = \frac{2+1}{2-1}\) = 3
C. \(<3> = \frac{3+1}{3-1}\) = 2
D. \(<4> = \frac{4+1}{4-1}\) = \(\frac{5}{3}\)
E. \(<5> = \frac{5+1}{5-1}\) = \(\frac{6}{4}\) = \(\frac{3}{2}\)
So, correct answer is option B.
24 Aug 2022, 10:19
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Given that \(<n> = \frac{n+1}{n-1}\) and we need to find which of the following has the greatest value
Let's take each option choice and find the value
A. <0>
To find <0> we need to compare what is inside <> in <0> and <n>
=> We need to substitute n with 0 in \(<n> = \frac{n+1}{n-1}\) to get the value of <0>
=> \(<0> = \frac{0+1}{0-1}\) = \(\frac{1}{-1}\) = -1
B. <2> = \(\frac{2+1}{2-1}\) = \(\frac{3}{1}\) = 3
C. <3> = \(\frac{3+1}{3-1}\) = \(\frac{4}{2}\) = 2
D. <4> = \(\frac{4+1}{4-1}\) = \(\frac{5}{3}\) = 1.67
E. <5> = \(\frac{5+1}{5-1}\) = \(\frac{6}{4}\) = 1.5
Clearly, B is the largest
So, Answer will be B
Hope it helps!
Watch the following video to learn the Basics of Functions and Custom Characters
Let's take each option choice and find the value
A. <0>
To find <0> we need to compare what is inside <> in <0> and <n>
=> We need to substitute n with 0 in \(<n> = \frac{n+1}{n-1}\) to get the value of <0>
=> \(<0> = \frac{0+1}{0-1}\) = \(\frac{1}{-1}\) = -1
B. <2> = \(\frac{2+1}{2-1}\) = \(\frac{3}{1}\) = 3
C. <3> = \(\frac{3+1}{3-1}\) = \(\frac{4}{2}\) = 2
D. <4> = \(\frac{4+1}{4-1}\) = \(\frac{5}{3}\) = 1.67
E. <5> = \(\frac{5+1}{5-1}\) = \(\frac{6}{4}\) = 1.5
Clearly, B is the largest
So, Answer will be B
Hope it helps!
Watch the following video to learn the Basics of Functions and Custom Characters
