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For all integers x and y, the operation is defined by x y =

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For all integers x and y, the operation is defined by x y =  [#permalink]

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New post Updated on: 02 Nov 2009, 11:53
2
00:00
A
B
C
D
E

Difficulty:

  65% (hard)

Question Stats:

60% (01:14) correct 40% (01:07) wrong based on 162 sessions

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For all integers x and y, the operation  is defined by xy = (x+2)^2 + (y+3)^2. What is the value of integer t?

(1) t  2 = 74
(2) 2  t = 80

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Originally posted by hrish88 on 02 Nov 2009, 11:13.
Last edited by hrish88 on 02 Nov 2009, 11:53, edited 1 time in total.
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Re: Operators Problem  [#permalink]

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New post 02 Nov 2009, 11:29
hrish88 wrote:
For all integers x and y, the operation  is defined by xy = (x+2)2 + (y+3)2. What is the
value of integer t?
(1) t  2 = 74
(2) 2  t = 80


A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is
sufficient.
D. EACH statement ALONE is sufficient.
E. Statements (1) and (2) TOGETHER are NOT sufficient


if expression is for square then will go with D. both give t=5
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Re: Operators Problem  [#permalink]

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New post 02 Nov 2009, 11:55
Yeah its a square.Already edited the post.
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For all integers x and y, the operation is defined by x y =  [#permalink]

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New post 02 Nov 2009, 12:38
2
1
For all integers x and y, the operation  is defined by xy = (x+2)^2 + (y+3)^2. What is the value of integer t?

(1) t  2 = 74 --> (t + 2)^2 + (2 + 3)^2 = 74 --> t^2 + 4t - 45 = 0 --> t = 5 OR t = -9. Two values for t. Not sufficient.

(2) 2  t = 80 --> (2 + 2)^2 + (t + 3)^2 = 80 --> t^2 +6t - 55 = 0 --> t = 5 OR t = -11. Two values for t. Not sufficient.

(1)+(2) t=5. Sufficient.

Answer: C.
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Re: Operators Problem  [#permalink]

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New post 02 Nov 2009, 18:52
I'm getting C as well

No point of retyping a Bunuel said it best

both are squared but don't forget the parenthesis can be negative since the number will be squared
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Re: For all integers x and y, the operation is defined by x y =  [#permalink]

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New post 28 Dec 2018, 21:41
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Re: For all integers x and y, the operation is defined by x y =   [#permalink] 28 Dec 2018, 21:41
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