For all numbers p and q (where p 0 ), the operation $ is defined as

Question

For all numbers p and q (where p ≠ 0 ), the operation $ is defined as  p \$ q = (p-1)^{(q-1)} . What is the value of  (p +1) \$ (q +1) ?

(1) p =1

(2) q = 0

gmatophobia · Answer

Given  :

p $ q =  (p-1)^{(q-1)}

Statement 1

(1)  p =1

p + 1 = 1 + 1 = 2

(p +1) $ (q +1)  = (2 - 1) ^{(q + 1 - 1)} = 1^{q} = 1

The statement alone is sufficient. We can eliminate B, C, and E.

Statement 2

(2)  q = 0

q + 1 = 0 + 1 = 1

(p +1) $ (q +1)  = (p + 1 - 1) ^{(1 - 1)} = p^{0} = 1

The statement alone is sufficient.

Option D

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