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Math Expert V
Joined: 02 Sep 2009
Posts: 64314
For all numbers x and y, the function x#y = (x+2)(y-1). What is the va  [#permalink]

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Difficulty:   25% (medium)

Question Stats: 78% (01:17) correct 22% (00:53) wrong based on 27 sessions

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For all numbers x and y, the function x#y = (x+2)(y-1). What is the value of 2#[3#(-1#1)]?

A. -44
B. -24
D. 0
C. 16
E. 28

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Director  D
Joined: 25 Jul 2018
Posts: 719
For all numbers x and y, the function x#y = (x+2)(y-1). What is the va  [#permalink]

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For all numbers x and y, the function x#y = (x+2)(y-1). What is the value of 2#[3#(-1#1)]?

—>(—1#1) = (—1+2)(1–1)= 0

—>( 3#0)= (3+2)(0–1)= —5

—>( 2#—5)= (2+2)(—5–1) = —24

Posted from my mobile device For all numbers x and y, the function x#y = (x+2)(y-1). What is the va   [#permalink] 24 Jan 2020, 02:05

# For all numbers x and y, the function x#y = (x+2)(y-1). What is the va  