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10 Dec 2018, 00:55
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B
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For all real numbers a and b, the operation ⊕ is defined by a ⊕ b = 2a – b. What is the absolute value of the difference between (3 ⊕ 1) ⊕ 2 and 6 ⊕ 3?
A. 0
B. 1
C. 2
D. 3
E. 4
A. 0
B. 1
C. 2
D. 3
E. 4
Chethan92
Joined: 18 Jul 2018
Last visit: 21 Apr 2022
Posts: 899
Own Kudos:
Given Kudos: 95
Location: India
Concentration: Operations, General Management
Schools: IIMB EPGP'22 (M)
GMAT 1: 590 Q46 V25
GMAT 2: 690 Q49 V34
WE:Engineering (Energy)
Products:
10 Dec 2018, 01:13
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3 ⊕ 1 = 2*3 - 1 = 5
5 ⊕ 2 = 5*2 - 2 = 8
6 ⊕ 3 = 6*2 - 3 = 9
Absolute difference = |8-9| = 1
B is the answer.
5 ⊕ 2 = 5*2 - 2 = 8
6 ⊕ 3 = 6*2 - 3 = 9
Absolute difference = |8-9| = 1
B is the answer.
Archit3110
Major Poster
10 Dec 2018, 04:09
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Bunuel
solve as per given expression
we get in the end 8-9 = -1
absolute value would be l-1l = 1 IMO B
