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# For an integer n greater than 1, n* denotes the product

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Manager
Joined: 13 Jun 2012
Posts: 202
Location: United States
WE: Supply Chain Management (Computer Hardware)
For an integer n greater than 1, n* denotes the product  [#permalink]

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26 Mar 2015, 03:07
1
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Difficulty:

45% (medium)

Question Stats:

64% (01:36) correct 36% (02:08) wrong based on 203 sessions

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For an integer n greater than 1, n* denotes the product of all the integers from 1 to n inclusive. How many prime numbers are there between 7*+2 and 7*+7, inclusive ?

A. 0
B. 1
C. 2
D. 3
E. 4
Math Expert
Joined: 02 Sep 2009
Posts: 57290
Re: For an integer n greater than 1, n* denotes the product  [#permalink]

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26 Mar 2015, 03:47
4
1
Turkish wrote:
For an integer n greater than 1, n* denotes the product of all the integers from 1 to n inclusive. How many prime numbers are there between 7*+2 and 7*+7, inclusive ?

A. 0
B. 1
C. 2
D. 3
E. 4

Given that n* denotes the product of all the integers from 1 to n, inclusive so, 7* + 2 = 7! + 2 and 7* + 7 = 7! + 7.

Now, notice that we can factor out 2 our of 7! + 2 so it cannot be a prime number, we can factor out 3 our of 7! + 3 so it cannot be a prime number, we can factor out 4 our of 7! + 4 so it cannot be a prime number, ... The same way for all numbers between 7! + 2 and 7! +7, inclusive. Which means that there are no primes in this range.

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Joined: 07 Aug 2011
Posts: 510
GMAT 1: 630 Q49 V27
Re: For an integer n greater than 1, n* denotes the product  [#permalink]

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26 Mar 2015, 04:58
1
Turkish wrote:
For an integer n greater than 1, n* denotes the product of all the integers from 1 to n inclusive. How many prime numbers are there between 7*+2 and 7*+7, inclusive ?

A. 0
B. 1
C. 2
D. 3
E. 4

None. as 7! is multiple of all numbers in the set $${1,2,3,4,5,6,7}$$ so when you add any of these number to the 7! you will always a multiple of one the numbers in the set.

similar question : does-the-integer-k-have-a-factor-p-such-that-1-p-k-126735.html
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Joined: 06 Mar 2015
Posts: 13
Re: For an integer n greater than 1, n* denotes the product  [#permalink]

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27 Mar 2015, 06:48
Bunuel wrote:
Turkish wrote:
For an integer n greater than 1, n* denotes the product of all the integers from 1 to n inclusive. How many prime numbers are there between 7*+2 and 7*+7, inclusive ?

A. 0
B. 1
C. 2
D. 3
E. 4

Given that n* denotes the product of all the integers from 1 to n, inclusive so, 7* + 2 = 7! + 2 and 7* + 7 = 7! + 7.

Now, notice that we can factor out 2 our of 7! + 2 so it cannot be a prime number, we can factor out 3 our of 7! + 3 so it cannot be a prime number, we can factor out 4 our of 7! + 4 so it cannot be a prime number, ... The same way for all numbers between 7! + 2 and 7! +7, inclusive. Which means that there are no primes in this range.

Hi Bunuel,

Based on the concept you mentioned that we can take a factor out from each number which results in no prime numbers between 7!+2 and 7!+7, can we say that if we add to 7! a number which is not a factor of 7* then the resultant number will be prime no.?

e.g. can we say 7!+11 or 7!+13 are prime numbers? Thanks in advance.
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Joined: 17 Feb 2015
Posts: 27
GPA: 3
Re: For an integer n greater than 1, n* denotes the product  [#permalink]

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27 Mar 2015, 07:07
1
gmatkiller88 wrote:
Bunuel wrote:
Turkish wrote:
For an integer n greater than 1, n* denotes the product of all the integers from 1 to n inclusive. How many prime numbers are there between 7*+2 and 7*+7, inclusive ?

A. 0
B. 1
C. 2
D. 3
E. 4

Given that n* denotes the product of all the integers from 1 to n, inclusive so, 7* + 2 = 7! + 2 and 7* + 7 = 7! + 7.

Now, notice that we can factor out 2 our of 7! + 2 so it cannot be a prime number, we can factor out 3 our of 7! + 3 so it cannot be a prime number, we can factor out 4 our of 7! + 4 so it cannot be a prime number, ... The same way for all numbers between 7! + 2 and 7! +7, inclusive. Which means that there are no primes in this range.

Hi Bunuel,

Based on the concept you mentioned that we can take a factor out from each number which results in no prime numbers between 7!+2 and 7!+7, can we say that if we add to 7! a number which is not a factor of 7* then the resultant number will be prime no.?

e.g. can we say 7!+11 or 7!+13 are prime numbers? Thanks in advance.

Hi gmatkiller88,

Not necessarily so. Here is a counter example, 3! + 19 = 25, not prime.
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Joined: 06 Mar 2015
Posts: 13
Re: For an integer n greater than 1, n* denotes the product  [#permalink]

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27 Mar 2015, 08:10
shreyast wrote:
gmatkiller88 wrote:
Turkish wrote:
For an integer n greater than 1, n* denotes the product of all the integers from 1 to n inclusive. How many prime numbers are there between 7*+2 and 7*+7, inclusive ?

Hi Bunuel,

Based on the concept you mentioned that we can take a factor out from each number which results in no prime numbers between 7!+2 and 7!+7, can we say that if we add to 7! a number which is not a factor of 7* then the resultant number will be prime no.?

e.g. can we say 7!+11 or 7!+13 are prime numbers? Thanks in advance.

Hi

Not necessarily so. Here is a counter example, 3! + 19 = 25, not prime. gmatkiller88,

Ok. So I guess in such cases we need to check each number individually to decide if the number is prime or not. Thanks.
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Re: For an integer n greater than 1, n* denotes the product  [#permalink]

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19 Feb 2016, 05:27
2
I did it this way
7!+2=2(7*6*5*4*3*1+1)=this will not be prime
7!+3=3(7*6*5*4*2*1+1)=this will not be prime
.......
7!+7=7(7*6*5*4*2*1+1)=same,not prime as it is multiple of 7

+1 for kudosssss
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Re: For an integer n greater than 1, n* denotes the product  [#permalink]

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08 May 2018, 06:40
1
Top Contributor
1
Turkish wrote:
For an integer n greater than 1, n* denotes the product of all the integers from 1 to n inclusive. How many prime numbers are there between 7*+2 and 7*+7, inclusive ?

A. 0
B. 1
C. 2
D. 3
E. 4

7* = 7! = (7)(6)(5)(4)(3)(2)(1)

So, 7* + 2 = (7)(6)(5)(4)(3)(2)(1) + 2
= 2[(7)(6)(5)(4)(3)(1) + 1]
= some multiple of 2
So, 7* + 2 is NOT a prime number

7* + 3 = (7)(6)(5)(4)(3)(2)(1) + 3
= 3[(7)(6)(5)(4)(2)(1) + 1]
= some multiple of 3
So, 7* + 3 is NOT a prime number

7* + 4 = (7)(6)(5)(4)(3)(2)(1) + 4
= 4[(7)(6)(5)(3)(2)(1) + 1]
= some multiple of 4
So, 7* + 4 is NOT a prime number
.
.
.
.
7* + 7 = (7)(6)(5)(4)(3)(2)(1) + 7
= 7[(6)(5)(4)(3)(2)(1) + 1]
= some multiple of 7
So, 7* + 7 is NOT a prime number

ASIDE: You can assume that I was able to perform the same steps with 7* + 5 and 7* + 6

Cheers,
Brent
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Re: For an integer n greater than 1, n* denotes the product  [#permalink]

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12 Aug 2019, 11:49
Turkish wrote:
For an integer n greater than 1, n* denotes the product of all the integers from 1 to n inclusive. How many prime numbers are there between 7*+2 and 7*+7, inclusive ?

A. 0
B. 1
C. 2
D. 3
E. 4

Notice that n* (which is the same thing as n!) is divisible by all positive integers from 1 to n.

7* + 2 is divisible by 2 (since both 7* and 2 are divisible by 2)

7* + 3 is divisible by 3 (since both 7* and 3 are divisible by 3)

In general, 7* + k is divisible by k when k is between 2 and 7, inclusive (since 7* is divisible by k and k is divisible by k).

Therefore, none of the numbers between 7* + 2 and 7* + 7, inclusive, is a prime.

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Re: For an integer n greater than 1, n* denotes the product   [#permalink] 12 Aug 2019, 11:49
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