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For any integer x, [x] is defined by the equation [x] = x +

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For any integer x, [x] is defined by the equation [x] = x +  [#permalink]

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New post Updated on: 06 Jul 2013, 07:19
6
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A
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D
E

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Question Stats:

70% (01:42) correct 30% (01:51) wrong based on 203 sessions

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For any integer x, [x] is defined by the equation [x] = x + 1. which of the following is equal to

A. 0
B. 2
C. -2x-
D. 2x
E. 2x-

I'm not sure how to write this question down over here as it has different functions! Attached image. Kindly provide Explanations. Thanks!

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Originally posted by fozzzy on 06 Jul 2013, 06:10.
Last edited by Bunuel on 06 Jul 2013, 07:19, edited 1 time in total.
Edited the question.
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Re: For any integer X, [x] is defined by the equation [x] = x+  [#permalink]

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New post 06 Jul 2013, 06:14
2
\(([x])^2=(x+1)^2\)
\([x^2]=x^2+1\)

\(([x])^2-[x^2]=x^2+2x+1-x^2-1=2x\)
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Re: For any integer x, [x] is defined by the equation [x] = x +  [#permalink]

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New post 06 Jul 2013, 07:23
fozzzy wrote:
For any integer x, [x] is defined by the equation [x] = x + 1. which of the following is equal to

A. 0
B. 2
C. -2x-
D. 2x
E. 2x-

I'm not sure how to write this question down over here as it has different functions! Attached image. Kindly provide Explanations. Thanks!



DS Functions and Custom Characters questions: search.php?search_id=tag&tag_id=40
PS Functions and Custom Characters questions: search.php?search_id=tag&tag_id=61

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Hope it helps.
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For any integer x, [x] is defined by the equation [x] = x +  [#permalink]

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New post 18 Oct 2017, 02:09
Plugin in value of x
Let x=2
representing x bar with=Ẍ =x+1
\((Ẍ)^2\)-{\((x)^2\)}- this part the one in the curly bracket the value of x has to be first squared and then represented in Ẍ form(\((2)^2\)+1)
\((2+1)^2\)-(4+1)
\((3)^2\)-(5)=4
9-5=4
now put x=2 in the given answer choices only 2x=4 answer D.
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For any integer x, [x] is defined by the equation [x] = x + &nbs [#permalink] 18 Oct 2017, 02:09
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