for any triangle T in the xy-cordinate plane, the centre of

Question

for any triangle T in the xy-cordinate plane, the centre of T is defined a to be the point whose x-cordinate is the average of the x-cordinate of the vertices of T and whose Y-cordinate is the average of the y-cordinates of the vertices of T. If a certain triangle has vertices at the point (0,0)and (6,0) and centre at the point (3,2), what are the cordinates of the remainig vertex ?

1. (3,4)
2. (3,6)
3. (4,9)
4. (6,4)
5. (9,6)

1. (3,4)
2. (3,6)
3. (4,9)
4. (6,4)
5. (9,6)

misterJJ2u · Answer

1 (or A)

The mid-point is the average of the X vertices and the Y vertices. 
Based on the given info, the baseline of the triangle has length = 6 and the mid-point has length = 3 and height 2, meaning the highest point should be 4. 
Therefore, last unknown vertex should be (3,4) or A.

blog · Answer

answer is 2 . . .

neelesh · Answer

(0+6+x)/3 = 3 => x = 3

(0+0+y)/3 = 2 => y = 6.

(3,6) is the third vertex.

B.

for any triangle T in the xy-cordinate plane, the centre of

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