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For each landscaping job that takes more than 4 hours, a [#permalink]

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08 Oct 2009, 17:15

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59% (02:08) correct
41% (01:23) wrong based on 196 sessions

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For each landscaping job that takes more than 4 hours, a certain contractor charges a total of r dollars for the first 4 hours plus 0.2*r dollars for each additional hour or fraction of an hour where r > 100, Did a particular landscaping job took more than 10 hours.

(1) The contractor charges a total of $288 for the job. (2) The contractor charges a total of 2.48r dollars for the job.

For each landscaping job that takes more than 4 hours, a certain contractor charges a total of r dollars for the first 4 hours plus 0.2r dollars for each additional hour or fraction of an hour where r > 100, Did a particular landscaping job took more than 10 hours.

A) The contractor charges a total of $288 for the job. B) The contractor charges a total of 2.4r dollars for the job.

Given: \(r>100\) Question: is \(t>10\)?

(1) \(r+0.2r(t-4)=288\) --> \(t=\frac{1440-r}{r}\) --> if \(r=101\), then \(t>10\) but if \(r=200\), then \(t<10\). Not sufficient.

Re: For each landscaping job that takes more than 4 hours, a [#permalink]

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07 Jun 2010, 02:52

Say total number of hours the job took = x

(1) \(r + 0.2r*(X-4) = 288\)

The prompt is for a constraint on X. Without knowing the value of r, you cannot determine any possible value for x. Eg. If r = 288, X = 4 If r = 100, X is more than 13. --> INSUFF

Re: For each landscaping job that takes more than 4 hours, a [#permalink]

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05 Jun 2014, 06:29

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Re: For each landscaping job that takes more than 4 hours, a [#permalink]

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04 Oct 2015, 15:52

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
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Re: For each landscaping job that takes more than 4 hours, a [#permalink]

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01 Oct 2016, 16:15

Hello All,

On this question, can we manipulate the question stem to say:

Is the total amount paid = r + 0.2r * 6 ----> r +1.2r ----> 2.2r ( so the question is asking if the money paid was 2.2r) This was derived from breaking down the 10hrs into portions of 4 and 6hrs respectively

Stmt 1 just gives a figure and does not consider r - hence insufficient

So Stmt 2 gives us a direct correlation between 2.2r and 2.4r - and is sufficient

Re: For each landscaping job that takes more than 4 hours, a [#permalink]

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08 Sep 2017, 18:52

Bunuel wrote:

mrsmarthi wrote:

For each landscaping job that takes more than 4 hours, a certain contractor charges a total of r dollars for the first 4 hours plus 0.2r dollars for each additional hour or fraction of an hour where r > 100, Did a particular landscaping job took more than 10 hours.

A) The contractor charges a total of $288 for the job. B) The contractor charges a total of 2.4r dollars for the job.

Given: \(r>100\) Question: is \(t>10\)?

(1) \(r+0.2r(t-4)=288\) --> \(t=\frac{1440-r}{r}\) --> if \(r=101\), then \(t>10\) but if \(r=200\), then \(t<10\). Not sufficient.

For each landscaping job that takes more than 4 hours, a certain contractor charges a total of r dollars for the first 4 hours plus 0.2r dollars for each additional hour or fraction of an hour where r > 100, Did a particular landscaping job took more than 10 hours.

A) The contractor charges a total of $288 for the job. B) The contractor charges a total of 2.4r dollars for the job.

Given: \(r>100\) Question: is \(t>10\)?

(1) \(r+0.2r(t-4)=288\) --> \(t=\frac{1440-r}{r}\) --> if \(r=101\), then \(t>10\) but if \(r=200\), then \(t<10\). Not sufficient.

We are told that "For each landscaping job that takes more than 4 hours, a certain contractor charges a total of r dollars for the first 4 hours plus 0.2r dollars for each additional hour..."

So, if the job takes 6 hours first 4 hours cost $r and each of the remaining (6 - 4) = 2 hours cost $0.2r.
_________________

For each landscaping job that takes more than 4 hours, a [#permalink]

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03 Oct 2017, 05:15

hi experts, I am confused about statement #1, here is my approach, please point out my fault

Suppose H represents the total working time r + 0.2r(H -4 ) = 228 228 = 0.2r(6+H) 0.2r = 228/(6+H)

because r>100, so 0.2r>20, we can get 228/(6+H) > 20 because 6+H > 0 so 228> 20*(6+H) 57*4 > 4*5*(6+H) 57>6+H H< 5.4 that must not be greater than 10 so I think statement #1 is sufficient

hi experts, I am confused about statement #1, here is my approach, please point out my fault

Suppose H represents the total working time r + 0.2r(H -4 ) = 228 228 = 0.2r(6+H) 0.2r = 228/(6+H)

because r>100, so 0.2r>20, we can get 228/(6+H) > 20 because 6+H > 0 so 228> 20*(6+H) 57*4 > 4*5*(6+H) 57>6+H H< 5.4 that must not be greater than 10 so I think statement #1 is sufficient

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